dictionary - 按列表过滤 Groovy 映射

Question

在 groovy 中有一种简单的方法可以通过列表过滤地图的索引。

produce_map        = ["grapes":"fruit","apple":"fruit","tomato":"vegetable","peas:"vegetable"]
green_produce_list = ["grapes","apples",'peas']

<magic code>

//desired result
filterd_map = ['apple':'fruit','grapes':'fruit','peas':'vegetable'] 

标签： dictionarygroovyfilter

Answer 1

使用subMap：

创建一个包含给定键的子映射。此方法类似于 List.subList() 但使用键而不是索引范围。原始地图没有改变。

def orig = [1:10, 2:20, 3:30, 4:40]
assert orig.subMap([1, 3] as int[]) == [1:10, 3:30]
assert orig.subMap([2, 4] as Integer[]) == [2:20, 4:40]
assert orig.size() == 4