java - 计算出现次数。(初学者)
问题描述
好的,我是 java 的初学者,在柜台上苦苦挣扎。我正在尝试查找计数并打印翻转硬币正面和反面的出现次数。当我运行我的代码时,它会在每一行打印每个事件的发生情况。我希望它是一个累积计数并在最后打印。如果能帮忙谢谢!Ps:我还没有实现tailCounter,因为我想先弄清楚正面。
import java.util.Random;
import java.util.Scanner;
public class InClass7_1
{
public static void main(String[] args)
{
int flipcount;
Scanner scannerObject = new Scanner(System.in);
System.out.println ("Enter a number of times to flip the coin");
flipcount = scannerObject.nextInt();
Random randomGenerator = new Random();
int counter = 1;
while (counter <= flipcount)
{
System.out.print("Flip number " + counter + ": ");
int coinFlip = randomGenerator.nextInt(2);
int headCounter = 0;
int tailCounter = 0;
if (coinFlip == 1)
{
System.out.println("Heads");
}
else
{
System.out.println("Tails");
}
counter++;
if (coinFlip == 1)
headCounter++;
System.out.println("Times head was flipped: " + headCounter);
}
}
}
解决方案
将headCounter
andtailCounter
变量移到 while 循环上方,并根据它们在 if-else 构造中的外观递增。将 print 语句移到 while 循环下方。
public static void main(String[] args) {
int flipcount;
Scanner scannerObject = new Scanner(System.in);
System.out.println("Enter a number of times to flip the coin");
flipcount = scannerObject.nextInt();
Random randomGenerator = new Random();
int counter = 1;
int headCounter = 0;
int tailCounter = 0;
while (counter <= flipcount) {
System.out.print("Flip number " + counter + ": ");
int coinFlip = randomGenerator.nextInt(2);
if (coinFlip == 1) {
System.out.println("Heads");
headCounter++;
} else {
System.out.println("Tails");
tailCounter++;
}
counter++;
}
System.out.println("Times head was flipped: " + headCounter);
System.out.println("Times tails was flipped: " + tailCounter);
}
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