c++ - 如何在不混淆字段的情况下声明复数？

Question

我尝试创建复数，但无论出于何种原因，它们总是出现具有虚值的实部和虚部归零。例如，我希望这个小测试应用程序能够打印多个 (1,2) 实例，但无论我如何尝试接近它，我得到的都是 (2,0)。

#include "stdafx.h"
#include <complex>
#include <iostream>
using namespace std;
int main()
{
    std::complex<double>** complexdouble_c;
    complexdouble_c = new std::complex<double>*[5];
    for (int i = 0; i < 5; ++i)
        complexdouble_c[i] = new std::complex<double>[2];

    for (int i = 0; i < 5 && i < 15; i++) {
        for (int j = 0; j < 2 && j < 15; j++) {
                double real = 1;
                double imag = 2;
                complexdouble_c[i][j] = (real, imag);
            }
        }
    for (int i = 0; i < 5 && i < 15; i++) {
        for (int j = 0; j < 2 && j < 15; j++) {
            std::cout << complexdouble_c[i][j];
        }
        std::cout << "\n";
    }
    std::complex<double> complexdouble;
    double real = 1.0;
    double imag = 2.0;
    complexdouble = (real, imag);
    std::cout << complexdouble;
    std::cout << complexdouble.real();
    std::cout << complexdouble.imag();
    getchar();
}

标签： c++

Answer 1

以这种格式声明。这将给出以下输出

std::complex<double> c(1, 2);
// 1 + 2i