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python - 下拉列表依赖于另一个下拉 tkinter

问题描述

我有一个包含汽车品牌的列表，另一个包含这些品牌的型号名称的列表。我想要两个下拉列表。首先选择品牌，然后在第二个下拉列表中选择型号。但只是所选品牌的型号。我得到了以下代码。

import tkinter as tk

brands = ["Bugatti","VW","Opel","Porsche"]
models = [["Veyron","Chiron"],
          ["Golf","Passat","Polo","Caddy"],
          ["Insignia","Corsa","Astra"],
          ["Taycan","Cayenne","911"]] 

root = tk.Tk()
canvas = tk.Canvas(root, height=500, width= 500, bg="white")
canvas.pack()

tkvar = tk.StringVar(root)
tkvar.set('Choose')

popupMenu1 = OptionMenu(canvas, tkvar, *brands)
popupMenu1.pack()

def change_dropdown(*args):

    print("Chosen brand " + tkvar.get())

    for i in range(len(brands)):
        if tkvar.get() == brands[i]:
            print(models[i])

tkvar.trace('w', change_dropdown)
root.mainloop()

我现在如何使用列表模型中的信息创建第二个下拉列表。谢谢你的帮助。

标签： pythontkinterdrop-down-menu

解决方案

您可以使用 Combobox 制作依赖下拉列表

import tkinter
from tkinter import ttk
root = tkinter.Tk()
''' 
widgets are added here 
'''
brands = ["Bugatti","VW","Opel","Porsche"]

models = [["Veyron","Chiron"],
          ["Golf","Passat","Polo","Caddy"],
          ["Insignia","Corsa","Astra"],
          ["Taycan","Cayenne","911"]]

car_brand = ttk.Combobox(root, width=37, value=(brands))
car_brand.grid(row=3, column=1, columnspan=2, padx=10, pady=2, sticky='w')

def callback(eventObject):
    abc = eventObject.widget.get()
    car = car_brand.get()
    index=brands.index(car)
    car_model.config(values=models[index])

car_model = ttk.Combobox(root, width=37)
car_model.grid(row=4, column=1, columnspan=2, padx=10, pady=2, sticky='w')
car_model.bind('<Button-1>', callback)

root.mainloop()

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