首页 > 解决方案 > QueryDSL 按计算字段排序

问题描述

在我们的应用程序中,我们使用 querydsl 来获取实体并将它们转换为表示对象。此演示对象具有名为 的字段active。这取决于实体的某个日期是在今天之前(活动 = 假)还是今天之后(活动 = 真)。一切顺利。问题在于尝试按该表达式 ( QEntity.someDate > today) 进行排序时。这使得hibernate抛出这个错误:

org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: > near line 3, column 40 [select object.someField as someAlias, (object.someDate > ?1) as active, object as objectAlias
from com.example.Object object
order by object.someDate > ?1 asc]

我创建OrderSpecifier如下:

    @Override
    public OrderSpecifier<?> getOrderByClause(SortKey sortKey) {
        BooleanExpression expression = getBooleanPath(); // This is the expression: (object.someDate > ?1)
        if (sortKey.getSortOrder() == ESortOrder.ASCENDING) {
            return new OrderSpecifier(Order.ASC, expression);
        }
        return new OrderSpecifier(Order.DESC, expression);
    }

我也试过这样:

    @Override
    public OrderSpecifier<?> getOrderByClause(SortKey sortKey) {
        BooleanExpression expression = getBooleanPath();
        if (sortKey.getSortOrder() == ESortOrder.ASCENDING) {
            return new CaseBuilder().when(expression.isFalse()).then(1).otherwise(2).asc();
        }
        return new CaseBuilder().when(expression.isTrue()).then(1).otherwise(2).desc();
    }

这会导致类似的错误:

org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: > near line 3, column 40 [select object.someField as someAlias, (object.someDate > ?1) as active, object as objectAlias
from com.example.Object object
order by case when (object.someDate > ?1 = ?2) then ?3 else 2 end asc]

最后像这样:

    @Override
    public OrderSpecifier<?> getOrderByClause(SortKey sortKey) {
        BooleanExpression expression = getBooleanPath();
        if (sortKey.getSortOrder() == ESortOrder.ASCENDING) {
            return new CaseBuilder().when(expression.eq(true)).then(1).otherwise(2).asc();
        }
        return new CaseBuilder().when(expression.eq(true)).then(1).otherwise(2).desc();
    }

这会引发与前一个相同的错误

标签: javaquerydsl

解决方案


通过创建这样的 order 子句来修复它:

    @Override
    public OrderSpecifier<?> getOrderByClause(SortKey sortKey) {
        BooleanPath path = getBooleanPath();
        if (sortKey.getSortOrder() == ESortOrder.ASCENDING) {
            return path.asc();
        }
        return path.desc();
    }

    private BooleanPath getBooleanPath() {
        return Expressions.booleanPath(getFieldName());
    }

在我们的例子中,字段名称是字符串的别名"active"


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