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python - AttributeError：“int”对象没有属性“display”

问题描述

我正在尝试编写一个程序，将数字随机分配给三个不同的列表，然后在不同类的帮助下，调用函数“display()”，并显示各种结果。我有我的类和随机化的循环，但每次我尝试打印 display() 结果时，我都会收到一个错误，说没有属性“显示”。我尝试更改变量名称以查看是否有帮助，但错误仍然存​​在。

我的代码是：

    class Circle():
    def __init__(self, radius=1):
        self.__radius = radius

    def find_area(self):
        a = self.__radius * self.__radius * 3.142
        return(a)

    def setRadius(self, rad):
        self.__radius = rad

    def getRadius(self):
        return(self.__radius)

    def display(self):
        print("\nClass = Circle")
        print("The area for this circle is:\t")
        return(self.find_area())

class Square():
    def __init__(self, sside=2.3):
        self.__sside = sside

    def find_area(self):
        a = self.__sside * self.__sside 
        return(a)

    def setSSide(self, lw):
        self.__sside = lw

    def getSSide(self):
        return(self.__sside)

    def display(self):
        print("\nClass = Square")
        print("The area for this square is:\t")
        return(self.find_area())

class Cube():
    def __init__(self, cside=2):
        self.__cside = cside

    def find_surfacearea(self):
        sa = 6 * self.__cside * self.__cside
        return(sa)

    def setCSide(self, lwh):
        self.__cside = lwh

    def getCSide(self):
        return(self.__cside)

    def display(self):
        print("\nClass = Cube")
        print("The area for this cube is:\t")
        return(self.find_surfacearea())

x1 = Circle()
print(x1.display())

x2 = Square()
print(x2.display())

x3 = Cube()
print(x3.display())

#Lists and Loops
circlelist = []
squarelist = []
cubelist = []

circlecount = 0
squarecount = 0
cubecount = 0

for i in range (10):
    shape = random.randint(1, 3)
    number = random.randint(0, 10)

    if shape == 1:
        print("\n*Circle*")
        circlecount += 1
        circlelist.append(number)

    elif shape == 2:
        print("\n*Square*")
        squarecount += 1
        squarelist.append(number)

    else:
        print("\n*Cube*")
        cubecount += 1
        cubelist.append(number)

"""x = len(circlelist)
y = len(squarelist)
z = len(cubelist)

for i in range (x):
    circlelist[i].display()
    #print()

for i in range (y):
    squarelist[i].display()

for i in range (z):
    cubelist[i].display()"""

print("\nThe items in the circle list are:", circlelist)
print(len(circlelist))
print("The items in the square list are:", squarelist)
print(len(squarelist))
print("The items in the cube list are:", cubelist)
print(len(cubelist))

for i in range (len(circlelist)):
    circlelist[i].display()

"""for i in range (10):
    circlelist.display()
    squarelist.display()
    cubelist.display()"""

有人可以帮我看看我哪里可能出错了吗？

标签： pythonarrayslistloopsclass

解决方案

目前，您的列表只是数字列表。您不能display()在数字上运行该功能，它必须在您的一个对象上运行。这需要一个相对简单的改变。与其拥有一个数字列表，不如拥有一个对象列表。

在下面的代码中，我对其进行了更改，而不是在列表中附加一个数字，而是在适当的情况下附加一个随机数作为半径、sside、cside 的新对象。

for i in range (10):
    shape = random.randint(1, 3)
    number = random.randint(0, 10)

    if shape == 1:
        print("\n*Circle*")
        circlecount += 1
        circlelist.append(Circle(radius=number))

    elif shape == 2:
        print("\n*Square*")
        squarecount += 1
        squarelist.append(Square(sside=number))

    else:
        print("\n*Cube*")
        cubecount += 1
        cubelist.append(Cube(cside=number))

如何编辑__init__功能以在创建时显示：

    def __init__(self, radius=1):
        self.__radius = radius
        self.display()

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