c++ - 将数组结构、ofstream 和整数传递给函数
问题描述
在我开始之前,如果解决方案很简单,我想道歉。在编码方面,我是初学者。
当我尝试编译我的 c++ 代码时,我得到两个错误代码:
- 未定义对“outputFirstSheet(std::basic_ofstream&,int,Info*)”的引用
- 错误:1d 返回 1 个退出状态
这是我的代码:
#include <iostream>
#include <fstream>
#include <iomanip>
using namespace std;
struct Info
{
char hurricaneName[11];
int ID;
int life;
int date;
float avgWindSpeed;
float avgRainFall;
int totalTornadoes;
};
struct Tropicals
{
int ID;
};
void outputFirstSheet(ofstream&, int counter, Info*);
int main()
{
ifstream storms;
storms.open("storms.txt");
//This will count how many lines have information in them or are being used.
int counter = 0;
while (storms)
{
counter = counter + 1;
storms.ignore(256,'\n');
}
//This is the end of that program
Info names[counter];
//Both pieces of code below will allow me to go back to the beginning of the storms.txt file
storms.clear();
storms.seekg(0, ios::beg);
while (storms){
storms.get(names[0].hurricaneName, 11);
for(int a = 0; a < counter - 1 ; a++)
{
storms >> names[a].ID;
storms >> names[a].life;
storms >> names[a].date;
float wind = 0.0;
float sum = 0;
for (int b = 0; b < 5;b++)
{
storms >> wind;
sum = wind + sum;
}
names[a].avgWindSpeed = sum / 5;
float rain = 0, total = 0;
for (int c=0; c < 2; c++)
{
storms >> rain;
total = rain + total;
}
names[a].avgRainFall = total / 2;
storms >> names[a].totalTornadoes;
//Making sure that I skip to the next line
storms.ignore(256, '\n');
storms.get(names[a+1].hurricaneName, 11);
}
}
ofstream outfile;
outfile.open("Results.txt");
outfile << fixed << setprecision(2);
// Printing out all the info in the STORM SUMMARY SHEET
outputFirstSheet(outfile, counter, names);
return 0;
}
void outputFirstSheet(ofstream &outfile, int counter, Info names)
{
cout << "The program's results can be located in 'Results.txt'" << endl;
outfile << setw(70) << "STORM SUMMARY SHEET" << endl;
outfile << endl;
outfile << "Name" << setw(10) << "ID" << setw(20) << " Life " << setw(10) << "Date" << setw(20) << " Average " << setw(20) << " Average " << setw(20) << "Tornadoes" << setw(20) << "Storm Level" << endl;
outfile << " " << setw(10) << " " << setw(20) << "in days" << setw(10) << "Date" << setw(20) << "wind speed" << setw(20) << "rain fall" << setw(20) << " spawned " << setw(20) << " level " << endl;
//Start adding the data to the STORM SUMMARY SHEET
outfile << endl;
for(int i = 0; i < counter - 1; i++)
{
outfile << names.hurricaneName[i];
}
outfile << endl << endl << "This code was created by Guillermo Molina Matus" << endl << endl;
}
有错误的行是outputFirstSheet(outfile, counter, names);
This function is should be able to use ofstream,接收计数器信息和 Struct Info 名称变量,但由于某种原因,我一直收到错误消息。
有人可以让我知道我做错了什么吗?
解决方案
在函数定义中使用Info* 名称
此外,数组是使用指针传递的,因此您实际上不必为 Info 获取指针。您可以简单地传递 Info 数组并像接收带值的变量一样接收它。它使用指针。未制作数组的新副本。
推荐阅读
- sql - 如何将 sql 查询的结果保存到变量中,然后在脚本中使用它?
- html - 水平滑块 CSS 的最佳方法
- haskell - 如何卸载堆栈包
- flutter - Flutter 提供程序未更新 UI
- javascript - 使用来自 Javascript 的 ClojureScript core.async 通道
- android - 亚行没有采取任何行动
- asp.net-web-api - 可以使用 ASP.NET WEB API 上传图像,但在部署时不能
- java - 用于 https 请求的 Spring REST 模板与单元测试
- google-colaboratory - Google Colab 中的不完整图表
- r - 使用带有向量作为过滤器的 likert 包的 group.order