首页 > 解决方案 > 尽管 MySQL 数据库中有数据,但图像不显示

问题描述

目前,我的项目有问题。photo before在 MySQL 数据库中,有两个名为photo_afterBLOB的base64在将图像显示到 PHP 页面时,我使用它来解码图像。

主要问题是列中是否有数据photo_before或者photo_after它仍然显示' noimage.jpg '。我不知道为什么。下面是我的代码:

<?php
$report_id = $_GET['report_id'];


$sql = "SELECT * FROM report LEFT JOIN users ON report.badgeid = users.badgeid LEFT JOIN team ON team.team_id = users.team_id WHERE report_id = :report_id";
$query = $conn->prepare($sql);
$query->execute(array(':report_id' => $report_id));
while($row = $query->fetch(PDO::FETCH_ASSOC)){

    $report_id = $row["report_id"];
    $report_date = $row["report_date"];
    $task_name = $row["task_name"];
    $photo_before = $row["photo_before"];
    $photo_after = $row["photo_after"];
    $ot_start = $row["ot_start"];
    $ot_end = $row["ot_end"];
    $time_photo_before = $row["time_photo_before"];
    $time_photo_after = $row["time_photo_after"];
    $report_status = $row["report_status"];

}

?>

<tr>
  <td rowspan = '2'><b>Before Task</b></td>

  <?php
    if(!isset($row['photo_before']) || empty($row['photo_before'])) {
        echo "<td colspan='3'><img src='../../images/faces/noimage.png'/></td>";
      }else{ 
              echo "<td colspan='3'><img src='data:image/jpeg;base64,".$row['photo_before']."'/></td>"; 
      }
  ?>

</tr>
<tr>
  <td colspan='3'><?php echo "Time: <b>" .$time_photo_before."</b>"; ?></td>
</tr>
<tr>
  <td rowspan = '2'><b>After Task</b></td>
  <?php
    if(!isset($row['photo_after']) || empty($row['photo_after'])) {
        echo "<td colspan='3'><img src='../../images/faces/noimage.png'/></td>";
      }else{ 
              echo "<td colspan='3'><img src='data:image/jpeg;base64,".$row['photo_after']."'/></td>"; 
      }
  ?>
</tr>

标签: phpmysql

解决方案


似乎问题出在 Your 上if( the problem is here ),|| / 或逻辑发送真如果 0|1,1|0 和 1|1...检查你的 php 版本,".$row['photo_before']."你的 " 使用 " 或 ',我的使用'.$row['photo_before'].'


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