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java - 如何用引号，站点运算符和非引号分割字符串？

问题描述

我收到这样的用户请求

site:www.example.com \"hello world\" \"hi abc\" where are you

我想从这个字符串中提取并保存 url 然后从上面的字符串中删除它，它应该看起来像这样"hello world" "hi abc" where are you现在将剩余的字符串拆分为两个字符串数组

String str1 = {hello world, hi abc};
String str2 = {where, are, you};

我怎么能在java中做到这一点？用户查询可以是任何顺序。各种例子：

 "hi" excitement site:www.example.com \"hello world\" \"hi abc\" where are you "amazing"   
OR
    Hello World friends
OR
 Greeting is an "act of communication" human beings "intentionally"

标签： javastringparsing

解决方案

这是一个非常具体的问题，下面的逻辑可能对您有所帮助。我建议您在使用实际数据进行测试时完善这一点。

public static void main(String[] args) {
    String test1 = "site:www.example.com \"hello world\" \"hi abc\" where are you";
    String regex = "\\b(https?|ftp|file|site):[-a-zA-Z0-9+&@#/%?=~_|!:,.;]*[-a-zA-Z0-9+&@#/%=~_|]";
    String[] info = test1.split("\"");

    //read url
    String url;
    if (info.length > 0 && info[0].trim().matches(regex))
        url = info[0].trim();
    else
        throw new RuntimeException("Not a valid input");

    // read str1
    String[] info1 = Arrays.copyOfRange(info, 1, info.length - 1);
    String str1 = mkString(info1, ",");

    //read str2
    String[] info2 = info[info.length - 1].trim().split("\\s");
    String str2 = mkString(info2, ",");


    System.out.println("URL: " + url + " STR1: " + str1 + " STR2: " + str2);

}

// returns a delimited and curly parentheses {} enclosed string
public static String mkString(String[] input, String delimeter) {
    String result = "{";
    for (int i = 0; i < input.length - 1; i++) {
        if (input[i].trim().length() > 0) {
            result += (input[i] + delimeter);
        }
    }
    result += (input[input.length - 1] + "}");
    return result;
}

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