python - 在python中快速替换2个矩阵

Question

抱歉，如果这是一个简单的问题，我是 python 新手。我有一个字符串（单词数组）和一个二维单词，我将一个一个地替换它们，如下所示：

str="Jim is a good person"
# and will convert to:
parts=['Jim','is','a','good','person']

和一个二维数组，其中每个维度是一个单词数组，可以用部分中具有相同索引的元素替换。例如这样的：

replacement=[['john','Nock','Kati'],
             ['were','was','are'],
             ['a','an'],
             ['bad','perfect','awesome'],
             ['cat','human','dog']]

结果可能是这样的：

1: nike is a good person
2: John are an bad human
3: Kati were a perfect cat
and so on

实际上，我将用一些可能的单词替换句子的每个单词，然后对新句子进行一些计算。我需要实现所有可能的替换。

非常感谢。

标签： pythonarraysstringtextnlp

Answer 1

itertools.product可能是创建您正在寻找的所有组合的最佳选择。

让我们以您的替换清单为起点，了解可行的方法。获得您正在寻找的所有组合的方法可能看起来像这样

from itertools import product

word_options=[['john','Nock','Kati'],
             ['were','was','are'],
             ['a','an'],
             ['bad','perfect','awesome'],
             ['cat','human','dog']]

for option in product(*word_options):
    new_sentence = ' '.join(option)
    #do calculation on new_sentence

被迭代的每个选项都是一个元组，其中每个元素都是来自原始二维列表的每个单独子列表的单个选择。然后' '.join(option)将单个字符串组合成一个字符串，其中单词用空格分隔。如果您只是 print new_sentence，输出将如下所示。

john were a bad cat
john were a bad human
john were a bad dog
john were a perfect cat
john were a perfect human
john were a perfect dog
.
.
.
Kati are an perfect cat
Kati are an perfect human
Kati are an perfect dog
Kati are an awesome cat
Kati are an awesome human
Kati are an awesome dog