时间戳

首页 > 解决方案 > 给定一周中的几天，如何获取两个日期之间的所有日期？

javascript - 给定一周中的几天，如何获取两个日期之间的所有日期？

问题描述

首先，我知道这个问题与这个问题非常相似： 如何获取两个日期之间的所有星期日/星期一/星期二？

不过，我要问的是不同的，我正在尝试创建一个函数，其中星期几是一个变量，并且可以有多个，如下所示：

function findClassDays(daysOfWeek, firstDay, lastDay) {
  const classDays = [];

  return classDays;
}

firstDay和lastDay是 javascript 日期，而是daysOfWeek一个数组，其中包含 ddd 时刻格式的星期几（例如，数组可以是['Mon', 'Wed', 'Fri'].

daysOfWeek如果以前不知道星期几并且可能有多个，我怎么能找到这两个日期之间的所有日子？我在链接的问题上看到了当您知道日期时它是如何工作的，而且它只是一个，但是如果数组有任何天数组合，我找不到解决方案。

标签： javascript

解决方案

试穿这个尺寸：

function findClassDays(daysOfWeek, firstDay, lastDay) {
    var allDays = ["Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat"];

    //get indices of days provided
    var firstDayIndex = firstDay.getDay();
    var lastDayIndex = lastDay.getDay();

    //determine which days are acceptable
    var acceptableDays = [];
    for(var i = firstDayIndex; i != lastDayIndex; i = (i + 1) % allDays.length){
        acceptableDays[acceptableDays.length] = allDays[i];
    }
    acceptableDays[acceptableDays.length] = allDays[lastDayIndex];

    //return the intersection (overlap) of daysOfWeek and acceptableDays
    return daysOfWeek.filter(function(d){return acceptableDays.indexOf(d) > -1;});
}

或者，如果您需要实际的日期对象，而不仅仅是星期几作为字符串：

function findClassDays(daysOfWeek, firstDay, lastDay){
    var allDays = ["Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat"];

    var matchingDates = [];
    while(firstDay.getDay() != lastDay.getDay()){
        //if firstDay is in daysOfWeek
        if(daysOfWeek.indexOf(allDays[firstDay.getDay()]) > -1){
            //add it to matchingDates
            matchingDates[matchingDates.length] = firstDay;
        }

        //increment first day
        firstDay = new Date(firstDay.getTime() + 1000 * 60 * 60 * 24);
    }
    //don't forget to check the last day as well
    if(daysOfWeek.indexOf(allDays[lastDay.getDay()]) > -1){
        matchingDates[matchingDates.length] = firstDay;
    }

    return matchingDates;
}

推荐阅读