ruby - 如何找到包含所有元音的同一数组的两个元素

Question

我想迭代给定的数组，例如：

["goat", "action", "tear", "impromptu", "tired", "europe"]

我想查看所有可能的配对。

所需的输出是一个新数组，其中包含所有对，组合包含所有元音。此外，这些对应连接为输出数组的一个元素：

["action europe", "tear impromptu"]

我尝试了以下代码，但收到错误消息：

No implicit conversion of nil into string.

def all_vowel_pairs(words)
  pairs = []

  (0..words.length).each do |i|                       # iterate through words
    (0..words.length).each do |j|                   # for every word, iterate through words again
      pot_pair = words[i].to_s + words[j]         # build string from pair
      if check_for_vowels(pot_pair)               # throw string to helper-method.
        pairs << words[i] + " " + words[j]      # if gets back true, concatenade and push to output array "pairs"
      end
    end
  end
  pairs
end

# helper-method to check for if a string has all vowels in it
def check_for_vowels(string)
  vowels = "aeiou"
  founds = []
  string.each_char do |char|
    if vowels.include?(char) && !founds.include?(char)
      founds << char
    end
  end
  if founds.length == 5
    return true
  end
  false
end

标签： rubynested-loops

Answer 1