c++ - 了解 C 中的线程以及如何使用它们进行排序
问题描述
我有一个关于线程的问题,想知道是否有人可以帮助我。所以,我正在研究这段代码,对如何更改正在使用的线程数感到困惑:
// multi-threading
#include <iostream>
#include <pthread.h>
#include <time.h>
// number of elements in array
#define MAX 20
// number of threads
#define THREAD_MAX 4
using namespace std;
// array of size MAX
int a[MAX];
int part = 0;
// merge function for merging two parts
void merge(int low, int mid, int high)
{
int* left = new int[mid - low + 1];
int* right = new int[high - mid];
// n1 is size of left part and n2 is size
// of right part
int n1 = mid - low + 1, n2 = high - mid, i, j;
// storing values in left part
for (i = 0; i < n1; i++)
left[i] = a[i + low];
// storing values in right part
for (i = 0; i < n2; i++)
right[i] = a[i + mid + 1];
int k = low;
i = j = 0;
// merge left and right in ascending order
while (i < n1 && j < n2) {
if (left[i] <= right[j])
a[k++] = left[i++];
else
a[k++] = right[j++];
}
// insert remaining values from left
while (i < n1) {
a[k++] = left[i++];
}
// insert remaining values from right
while (j < n2) {
a[k++] = right[j++];
}
}
// merge sort function
void merge_sort(int low, int high)
{
// calculating mid point of array
int mid = low + (high - low) / 2;
if (low < high) {
// calling first half
merge_sort(low, mid);
// calling second half
merge_sort(mid + 1, high);
// merging the two halves
merge(low, mid, high);
}
}
// thread function for multi-threading
void* merge_sort(void* arg)
{
// which part out of 4 parts
int thread_part = part++;
// calculating low and high
int low = thread_part * (MAX / 4);
int high = (thread_part + 1) * (MAX / 4) - 1;
// evaluating mid point
int mid = low + (high - low) / 2;
if (low < high) {
merge_sort(low, mid);
merge_sort(mid + 1, high);
merge(low, mid, high);
}
}
// Driver Code
int main()
{
// generating random values in array
for (int i = 0; i < MAX; i++)
a[i] = rand() % 100;
// t1 and t2 for calculating time for
// merge sort
clock_t t1, t2;
t1 = clock();
pthread_t threads[THREAD_MAX];
// creating 4 threads
for (int i = 0; i < THREAD_MAX; i++)
pthread_create(&threads[i], NULL, merge_sort,
(void*)NULL);
// joining all 4 threads
for (int i = 0; i < 4; i++)
pthread_join(threads[i], NULL);
下面这部分特别难,因为我不确定这些“(MAX / 2, MAX/2 + (MAX-1-MAX/2)/2, MAX - 1);”是什么 实际工作。例如,我如何制作 2 个或 8 个线程?
// merging the final 4 parts
merge(0, (MAX / 2 - 1) / 2, MAX / 2 - 1);
merge(MAX / 2, MAX/2 + (MAX-1-MAX/2)/2, MAX - 1);
merge(0, (MAX - 1)/2, MAX - 1);
t2 = clock();
// displaying sorted array
cout << "Sorted array: ";
for (int i = 0; i < MAX; i++)
cout << a[i] << " ";
// time taken by merge sort in seconds
cout << "Time taken: " << (t2 - t1) /
(double)CLOCKS_PER_SEC << endl;
return 0;
}
在这种情况下我们该如何进行?
谢谢!
解决方案
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