javascript - 关联和合并同一部门的数组

Question

我正在开发一个应用程序，我需要根据第二个数组中提供的条件组合同一部门的对象并将关系附加到对象。

let inArr1 = [{"D1D2":"AND"},{"D3D4":"OR"}]
let inArr2 =[{"ID":"1","NAME":"KEN","DEPT1":"CSE"},
              {"ID":"2","NAME":"MARK","DEPT2":"IT"},
              {"ID":"3","NAME":"TOM","DEPT3":"ECE"},
              {"ID":"4","NAME":"SHIV","DEPT4":"LIB"},
              {"ID":"5","NAME":"TIM","DEPT5":"SEC"}
            ]

输出

 outArr ={ 
                 [{"ID":"1","NAME":"KEN","DEPT1":"CSE","REL":"AND"}, 
                  {"ID":"2","NAME":"MARK","DEPT2":"IT","REL":"AND"}], //Arr1
                 [{"ID":"3","NAME":"TOM","DEPT3":"ECE","REL":"OR"}, 
                  {"ID":"4","NAME":"SHIV","DEPT4":"LIB","REL":"OR"}], //Arr2
                 [{"ID":"5","NAME":"TIM","DEPT5":"SEC"}]              //Arr3
                }

代码：

let  condArr=[],outArr,i=1;

inArr1.forEach(condt => {
     let dept = Object.keys(condt)[0];
     let tmparr = dept.split("D");
     tmparr.shift()
     condArr.push(tmparr) 
   });

inArr2.forEach(condt => {
    if(condArr.includes(inArr2.D+i)){
        i++;
       outArr.push(inArr2);
    }
 });

标签： javascript

Answer 1

您的代码逻辑有点混乱，我建议您这样做

let inArr1 = [{"D1D2":"AND"},{"D3D4":"OR"},{"D5D6":"AND"}] 
let inArr2 =[{"ID":"1","NAME":"KEN","DEPT1":"CSE"},
              {"ID":"2","NAME":"MARK","DEPT2":"IT"},
              {"ID":"3","NAME":"TOM","DEPT3":"ECE"},
              {"ID":"4","NAME":"SHIV","DEPT4":"LIB"},
              {"ID":"5","NAME":"TIM","DEPT5":"SEC"},
              {"ID":"6","NAME":"TLA","DEPT6":"SEC"},
            ]

// first lets create object of ids as keys and conditions as values
const [keys, conditions] = inArr1.reduce((agg, cond, index) => {
   Object.entries(cond).forEach(([key, value]) => {
      key.split('D').forEach(v => { if (v) agg[0][v] = { value, index }})   
      agg[1].push([])
   })
   return agg
}, [{}, []]) // {1: "AND", 2: "AND", 3: "OR", 4: "OR"}
conditions.push([])

// and now just map over all elements and add condition if we found id from the keys
inArr2.forEach(item => {
   const cond = keys[item.ID]
   if (cond) conditions[cond.index].push({...item, REL: cond.value}) 
   else conditions[conditions.length - 1].push(item)
})

const res = conditions.filter(v => v.length)
console.log(res)