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python-3.x - 为什么我不能更换新的行分隔符？

问题描述

我正在开发将消息从应用程序发送到我们的 API 的 Python 电报客户端，我想排除一些单词。在这种情况下应该删除一些@logins 和#tag：

应该删除一些@logins 和#tag

这是我的代码：

for w in app.config['EXCLUDED_WORDS']:
    if w in data:
        data = data.replace(w, '')

很简单，对吧？我得到的结果（很多新行）：

很多新线路

我尝试了非常不同的 NL 分隔符，例如，#YoCrypto\n #YoCrypto\r #YoCrypto\r\n但它不起作用。所以这是我的print(data.encode('utf-8'))输出：

#TAG\n#YoCrypto\xd0\xa0laced \xd0\xb0dditional signal for Bitmex. I will remember to include both exchanges on the same signal for btcusd now on. My apologies for inconvenience.\xef\xbb\xbf@grandcchat\n@grandcsign\n@grandcmargin

我究竟做错了什么？

UPD 01.01.2020 有一些排除的词：['@grandcmargin\n', '@grandcsign\n', '@grandcchat\n', '#YoCrypto\n', 'По всем вопросам (For all questions, please contact): @NickolchenkoGCS']

我们应该在替换区域的开始和结束时留下一个中断，所以预期的输出应该是这样的：

#TAG\n\nPlaced additional signal for Bitmex. I will remember to include both exchanges on the same signal for btcusd now on. My apologies for inconvenience.\n\n[Picture from message]

标签： python-3.xreplaceutf-8newlinetelegram

解决方案

一种可能的解决方案是使用re模块并将单词加上任何其他换行符替换为空字符串。例如：

import re

data = b'''#TAG\n#YoCrypto\xd0\xa0laced \xd0\xb0dditional signal for Bitmex. I will remember to include both exchanges on the same signal for btcusd now on. My apologies for inconvenience.\xef\xbb\xbf@grandcchat\n@grandcsign\n@grandcmargin'''

words_to_remove = {'@grandcmargin', '@grandcsign', '@grandcchat', '#YoCrypto', 'По всем вопросам (For all questions, please contact): @NickolchenkoGCS'}

# decode the data (if not decoded already)
data = data.decode('utf-8')

# replace the words plus any aditional new-line character afterwards:
data = re.sub('|'.join(r'(?:[\ufeff]*{}\n*)'.format(re.escape(w)) for w in words_to_remove) , '\n', data)
data = re.sub(r'\n{3,}', r'\n\n', data) # remove excessive new-lines

print(data)

印刷：

#TAG

Рlaced аdditional signal for Bitmex. I will remember to include both exchanges on the same signal for btcusd now on. My apologies for inconvenience.

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