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python - OpenCV python：如何使用渐变和第一点画一条线？

问题描述

我正在尝试使用带有 opencv 的实时提要画一条线。我正在使用一帧并存储 x,y 坐标。我使用该点的下一帧的 x,y 坐标来计算梯度 ((y2-y1)/(x2-x1))。我想从第一个坐标直接到第二个坐标画一条直线，然后继续画一条轨迹。我目前可以使用 . 在两点之间画一条直线cv2.line()。我的代码如下。任何建议都会很棒！谢谢

import numpy as np
import math
import matplotlib.pyplot as plt

lower_red = np.array([-10,160,160])
upper_red = np.array([10,255,255])

oX, oY = 0,0

cap = cv2.VideoCapture(0)
if not cap.isOpened():
    print("Cannot open camera")
    exit()
while(1):
    ret, frame = cap.read()
    if not ret:
        print("Can't receive frame (stream end?). Exiting ...")
        break

    hsv = cv2.cvtColor(frame, cv2.COLOR_BGR2HSV)
    mask = cv2.inRange(hsv, lower_red, upper_red)
    #ret, thresh = cv2.threshold(mask, 80, 255, cv2.THRESH_BINARY)
    contours, _ = cv2.findContours(mask, cv2.RETR_TREE, cv2.CHAIN_APPROX_NONE)

    if len(contours) != 0:
        c = max(contours, key = cv2.contourArea)
        x1, y1, w, h = cv2.boundingRect(c)
        x2, y2 = x1 + w, y1 + h
        cv2.rectangle(frame, (x1, y1), (x2, y2), (0, 255, 0), 2)
        x3, y3 = round((x1+x2)/2), round((y1+y2)/2)
        cv2.circle(frame, (x3,y3), 4, (255,0,0), 2)
        #print(x3, y3)

        if oX and oY != 0:
            try:
                angle = (x3-oX)/(y3-oY)
                cv2.line(frame,(oX,oY),(x3, y3),(0,255,255),2)
            except ZeroDivisionError:
                oX, oY = x3, y3

    oX, oY = x3, y3

    cv2.imshow('frame', frame)
    cv2.imshow('mask', mask)


    if cv2.waitKey(1) == ord('q'):
        break
# When everything done, release the capture
cap.release()
cv2.destroyAllWindows()

标签： pythonopencvlineopencv-python

解决方案

从这个答案中找到了一个解决方案，它在 c 中，转换为 python 并针对您的用例进行了修改。

给定两点在图像中绘制无限线的解决方案。

def slope(x1,y1,x2,y2):
    ###finding slope
    if x2!=x1:
        return((y2-y1)/(x2-x1))
    else:
        return 'NA'

def drawLine(image,x1,y1,x2,y2):

    m=slope(x1,y1,x2,y2)
    h,w=image.shape[:2]
    if m!='NA':
        ### here we are essentially extending the line to x=0 and x=width
        ### and calculating the y associated with it
        ##starting point
        px=0
        py=-(x1-0)*m+y1
        ##ending point
        qx=w
        qy=-(x2-w)*m+y2
    else:
    ### if slope is zero, draw a line with x=x1 and y=0 and y=height
        px,py=x1,0
        qx,qy=x1,h
    cv2.line(image, (int(px), int(py)), (int(qx), int(qy)), (0, 255, 0), 2)

您可以根据您的用例替换(px,py)为(x1,y1)或。(qx,qy)(x2,y2)

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