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postgresql - 在 Postgres 中使用带空格的列名的语法错误

问题描述

我正在尝试在架构下创建表。但是，我收到以下错误。

[代码：0，SQL 状态：42601] 错误：“VARCHAR”位置或附近的语法错误：120 [脚本位置：120 - 123]

我无法调试语法错误在哪里。您可以在下面找到 postgres 查询。

CREATE SCHEMA IF NOT EXISTS ebi_mut_db;

        CREATE TABLE IF NOT EXISTS ebi_mut_db.version_info (
        version INT, 
        download_date DATE, 
        download_url TEXT, 
        responsible TEXT);

        CREATE TABLE IF NOT EXISTS ebi_mut_db.mutations_affecting_interactions (
        Feature AC NOT NULL VARCHAR (20), 
        Feature short label VARCHAR (50), 
        Feature range(s) VARCHAR (50), 
        Original sequence CHAR (50), 
        Resulting sequence CHAR (50), 
        Feature type VARCHAR (100), 
        Feature annotation VARCHAR (255), 
        Affected protein AC VARCHAR (100), 
        Affected protein symbol VARCHAR (100), 
        Affected protein full name VARCHAR (100), 
        Affected protein organism VARCHAR (100), 
        Interaction participants VARCHAR (255), 
        PubMedID VARCHAR (100), 
        Figure legend VARCHAR (50), 
        Interaction AC VARCHAR (50),
        PRIMARY KEY (Feature AC);

谢谢

标签： postgresqldatabase-schemaddl

解决方案

列名中不能有空格。如果你真的想让你的生活变得更艰难，那么你必须引用它们，例如，"Feature AC"而不是Feature AC

NOT NULL属性在数据类型之后，

"Feature AC" VARCHAR (20) NOT NULL,

您还缺少)CREATE TABLE 语句末尾的关闭：

请忘记该char类型存在。它绝对没有任何优势，但有一些令人讨厌的惊喜。

所以整个陈述应该是：

CREATE TABLE IF NOT EXISTS ebi_mut_db.mutations_affecting_interactions 
(
  "Feature AC" VARCHAR (20) NOT NULL, 
  "Feature short label" VARCHAR (50), 
  "Feature range(s)" VARCHAR (50), 
  "Original sequence" VARCHAR (50), 
  "Resulting sequence" VARCHAR (50), 
  "Feature type" VARCHAR (100), 
  "Feature annotation" VARCHAR (255), 
  "Affected protein AC" VARCHAR (100), 
  "Affected protein symbol" VARCHAR (100), 
  "Affected protein full name" VARCHAR (100), 
  "Affected protein organism" VARCHAR (100), 
  "Interaction participants" VARCHAR (255), 
  "PubMedID" VARCHAR (100), 
  "Figure legend" VARCHAR (50), 
  "Interaction AC" VARCHAR (50),
  PRIMARY KEY (Feature AC)
);

但是你应该，真的，真的重新考虑你的列名。我强烈建议使用这样的东西：

CREATE TABLE IF NOT EXISTS ebi_mut_db.mutations_affecting_interactions 
(
  feature_ac varchar (20) not null, 
  feature_short_label varchar (50), 
  feature_range varchar (50), 
  original_sequence varchar (50), 
  resulting_sequence varchar (50), 
  feature_type varchar (100), 
  feature_annotation varchar (255), 
  affected_protein_ac varchar (100), 
  affected_protein_symbol varchar (100), 
  affected_protein_full_name varchar (100), 
  affected_protein_organism varchar (100), 
  interaction participants varchar (255), 
  pub_med_id varchar (100), 
  figure_legend varchar (50), 
  interaction_ac varchar (50),
  primary key (feature ac)
);

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