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首页 > 解决方案 > 致命的 Python 错误：无法获取 <_io.BufferedReader name=' 的锁'> 在解释器关闭时，可能是由于守护线程

python - 致命的 Python 错误：无法获取 <_io.BufferedReader name=' 的锁'> 在解释器关闭时，可能是由于守护线程

问题描述

我想编写一个python脚本，如果我没有通过输入命令输入任何值，那么它应该在30秒后为我的变量分配一个默认值，我的平台是windows 7

from func_timeout import func_timeout, FunctionTimedOut

def doit():

    value = input("enter")

try:
    doitReturnValue = func_timeout(5, doit)

except FunctionTimedOut:
    value = "default value"

这是我得到的错误：

"C:\Users\Arpit\PycharmProjects\Complete Test\venv\Scripts\python.exe" "C:/Users/Arpit/PycharmProjects/Complete Test/test_for_timeout.py"
enterFatal Python error: could not acquire lock for <_io.BufferedReader name='<stdin>'> at interpreter shutdown, possibly due to daemon threads
Python runtime state: finalizing (tstate=00000000003CAE20)

Thread 0x00000c18 (most recent call first):
  File "C:\Users\Arpit\AppData\Local\Programs\Python\Python38\lib\threading.py", line 1027 in _wait_for_tstate_lock
  File "C:\Users\Arpit\AppData\Local\Programs\Python\Python38\lib\threading.py", line 1015 in join
  File "C:\Users\Arpit\PycharmProjects\Complete Test\venv\lib\site-packages\func_timeout\StoppableThread.py", line 126 in run
  File "C:\Users\Arpit\AppData\Local\Programs\Python\Python38\lib\threading.py", line 932 in _bootstrap_inner
  File "C:\Users\Arpit\AppData\Local\Programs\Python\Python38\lib\threading.py", line 890 in _bootstrap

Thread 0x0000106c (most recent call first):
  File "C:/Users/Arpit/PycharmProjects/Complete Test/test_for_timeout.py", line 7 in doit
  File "C:\Users\Arpit\PycharmProjects\Complete Test\venv\lib\site-packages\func_timeout\dafunc.py", line 68 in funcwrap
  File "C:\Users\Arpit\AppData\Local\Programs\Python\Python38\lib\threading.py", line 870 in run
  File "C:\Users\Arpit\AppData\Local\Programs\Python\Python38\lib\threading.py", line 932 in _bootstrap_inner
  File "C:\Users\Arpit\AppData\Local\Programs\Python\Python38\lib\threading.py", line 890 in _bootstrap

Current thread 0x00001850 (most recent call first):
<no Python frame>

Process finished with exit code 3

标签： python

解决方案

如果你没有任何限制，你可以试试asyncio包。

有一个异步包aioconsole，它允许在异步执行其他任务的同时等待用户输入。

为了安装这个包，请运行：pip install aioconsole

以下代码将等待用户输入 30 秒。如果用户此时没有输入任何内容，它将继续 ( raise asyncio.TimeoutError) 并将值设置为默认值。

import asyncio
import aioconsole

async def main(main_loop):
    t = main_loop.create_task(aioconsole.ainput())
    try:
        await asyncio.wait_for(t, timeout=30)
        value = t.result()
    except asyncio.TimeoutError as _:
        value = "default value"
    print(value)
    return value

if __name__ == '__main__':
    l = asyncio.get_event_loop()
    value = l.run_until_complete(main(l))
    l.close()

关于你的代码，我已经尝试过了，它对我有用，只是做了一些小的改动：

from func_timeout import func_timeout, FunctionTimedOut
def doit():
    value = input("enter")
    return value  # Need to return the value.
try:
    value = func_timeout(5, doit)  # Set the return value to the same variable name
except FunctionTimedOut as _:
    value = "default value"
print(value)

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