首页 > 解决方案 > cmd批处理 - usebackq in for:要拆分的字符串从逗号分隔更改为空格分隔

问题描述

我想读取一个包含多个(未终止的)Kafka 主机的字符串,并使用 cmd 在单独的行中列出它们for

字符串是这样的:

host1:9092,host2:9092,host3:9092,...

我所拥有的是:

set /p BOOTSTRAPSERVERS="Bootstrap servers with port, separated by comma(by default localhost:9092): "
REM echo "%BOOTSTRAPSERVERS%"
if "%BOOTSTRAPSERVERS%"=="" set BOOTSTRAPSERVERS="localhost"

echo All the servers to connect: 
FOR /F "usebackq delims=," %%i in (`echo %BOOTSTRAPSERVERS%`) do (
    echo %%i
    echo.
)

但是,我只将所有主机放在一行中,空格分隔:

All the servers to connect:
host1:9092 host2:9092 host3:9092

为什么?

如果我打开@echo on,我会看到这个,这是没有意义的:

set /p BOOTSTRAPSERVERS="Bootstrap servers with port, separated by comma(by default localhost:9092): "
Bootstrap servers with port, separated by comma(by default localhost:9092): host1:9092,host2:9092,host3:9092

REM echo "host1:9092,host2:9092,host3:9092"

if "host1:9092,host2:9092,host3:9092" == "" set BOOTSTRAPSERVERS="localhost"

echo All the servers to connect:
All the servers to connect:

FOR /F "usebackq delims=," %i in (`echo host1:9092 host2:9092 host3:9092`) do (
echo %i
 echo.
)

(
echo host1:9092
 echo.
)
host1:9092

如果仔细观察,echo将字符串从逗号分隔变为空格分隔,when%BOOTSTRAPSERVERS%不是双引号。

如果是双引号,输出将是:

"host1:9092

为什么?

有没有更好的方法用分隔符分割字符串?

标签: batch-filecmdecho

解决方案


要按标准分隔符(SPACE、TAB、逗号)分割字符串,可以使用普通for循环(no /f):

set "bootstrapservers=host1:9092,host2:9092,host3:9092"
for %%a in (%bootstrapservers%) do echo %%a

输出:

host1:9092
host2:9092
host3:9092

注意set命令的语法(这样引号不会成为值的一部分)。相同的语法适用于set /pset /p "var=Prompt:"


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