r - 如何使用 ggplot 创建百分比堆叠形状

Question

有没有办法可以用ggplot2 geom_rect()图层做百分比堆积图？我有坐标，所以我创建了一个形状，我也有我的分离变量t，现在我想根据t. 换句话说，我想做百分比堆叠条形图，但不是条形图，而是自定义形状（在我的情况下，是简单的矩形）。我一直在尝试很多position="fill",stat="identity"和他们的品种，但没有任何成功。我想知道这是否可能，如果可以，我该如何实现？

df <- structure(list(x1 = c(4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 3, 3, 3, 
3, 3), x2 = c(6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 4, 4, 4, 4, 4), y1 = c(3, 
3, 3, 3, 3, 3, 3, 3, 3, 3, 1, 1, 1, 1, 1), y2 = c(5, 5, 5, 5, 
5, 5, 5, 5, 5, 5, 2, 2, 2, 2, 2), t = structure(c(1L, 1L, 1L, 
1L, 1L, 1L, 1L, 2L, 2L, 2L, 1L, 2L, 2L, 1L, 1L), .Label = c("a", 
"b"), class = "factor")), row.names = c("1", "2", "3", "4", "5", 
"6", "7", "8", "9", "10", "11", "12", "13", "14", "15"), class = "data.frame")

library(ggplot2)
ggplot() + 
    geom_rect(data=d, mapping=aes(xmin=x1, xmax=x2, ymin=y1, ymax=y2, fill = t))

预期结果

感谢您的时间！

标签： rggplot2ggplotly

Answer 1

这是所需绘图的工作代码，它使用 进行了一些编码dplyr，但它有效。

library(ggplot2)
library(tidyverse)

df1<-df %>%
  group_by(x1,y1,x2,y2,t) %>%
  count() %>% 
  ungroup() %>%
  group_by(x1,y1) %>%
  mutate(perc = n / sum(n),
         percLabel = paste(100 * perc,"%",sep = " "),
         transf = abs(x2-x1) * perc,
         newx1 = ifelse(t == "a", x1,x2-transf),
         newx2 = ifelse(t == "a", x1+transf,x2)) 


ggplot(df1,aes(xmin = newx1, 
               xmax = newx2, 
               ymin = y1, 
               ymax = y2, 
               fill = t)) + 
  geom_rect(col = "black") + 
  geom_text(aes(x = newx1 + ((newx2 - newx1)/2), 
                              y = y1 + ((y2 - y1)/2), 
                              label = percLabel)) + 
  labs(x="X",y="Y")