首页 > 解决方案 > 范围滑块:jQuery 更改值但滑块不移动

问题描述

我运行以下程序:

<!DOCTYPE html>
<html>
<head>
    <meta charset="UTF-8">
    <title> Slider </title>
    <!-- jQuery CDN https://code.jquery.com/ -->
    <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script> 
    <script type="text/javascript"src="https://code.jquery.com/ui/1.12.1/jquery-ui.js"></script>
    <script>
    $(document).ready(function() {
        console.debug("jQuery "+ (jQuery ? $().jquery : "NOT") +" loaded"); // jQuery version to console
        $('#slider1').slider({value: "11"});                                // initialize slider
        $("#slider1").slider("option", "value", 2);       
        $("#slider1" ).slider("value", 3 );
        var value = $( "#slider1" ).slider( "option", "value");    // show slider value 
        $('#sliderVal').text("Slider Value: "+value);

        $('#slider1').on('input', function(event) {                     // show slider value when changed
            var valSlider1 =  $(this).attr('id') +"   Value:" +$(this).val();
            $('#sliderVal').text(valSlider1);
        });
    });
    </script>
</head>
<body>
    <p> Slider </p> 
    <input type="range" class="sl" id="slider1"  min="0" max="100" value="99">  
    <p id="sliderVal">...</p                     //display value of slider
</body>
</html>

运行程序后,滑块的“拇指”仍然停留在 99 输出(id=sliderVal;倒数第二行)说:滑块值:3
我试过

 $('#slider1').slider({value: "11"});       
 $("#slider1").slider("option", "value", 2);       
 $("#slider1" ).slider("value", 3 );

它们都改变了滑块的值,但滑块拇指从不移动。当我用鼠标移动滑块的拇指时,会显示正确的值

标签: jqueryslider

解决方案


val()这样改$("#slider1").val(2);

$(document).ready(function() {
  $("#slider1").val(11);
  var value = $("#slider1").val();
  $('#sliderVal').text("Slider Value: " + value);

  $('#slider1').on('input', function(event) { 
    var valSlider1 = $(this).attr('id') + "   Value:" + $(this).val();
    $('#sliderVal').text(valSlider1);
  });
});

$('#change').click(function() {
  $("#slider1").val(2);
  $('#sliderVal').text("Slider Value: 2");
});
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<script type="text/javascript" src="https://code.jquery.com/ui/1.12.1/jquery-ui.js"></script>

<p> Slider </p>
<input type="range" class="sl" id="slider1" min="0" max="100" value="99">
<p id="sliderVal">
</p>

<button id="change">Change</button>


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