python - Django编辑模型实例找不到实例

问题描述

我正在制作食谱书。出于某种原因，每当我尝试从数据库中提取食谱进行编辑时，我都会收到一个错误，即找不到我指定的食谱。我正在使用蛞蝓，我的逻辑是我将从已经提取数据库信息的详细视图转到更新视图。我试图将我已经从 detailView 中提取的配方对象传递给 updateView，但是当我这样做时，它一直告诉我它找不到指定的配方。

views.py： 我在这里调用的基本视图只提供了一个默认的 post 方法来处理搜索，这样我就不必为我创建的每个视图都放入它，所以我有一些代码可重用性

class RecipeDetailView(BaseDetailView):
    model = Recipe
    template_name = 'RecipeBook/recipe_detail.html'
    context_object_name = 'recipe_view'
    queryset = None
    slug_field = 'slug'
    slug_url_kwarg = 'slug'

    def get_context_data(self, *args, **kwargs):
        context = super(RecipeDetailView, self).get_context_data()
        recipe = self.object
        recipe.ingredients = recipe.ingredients_list.split('\n')

        context['recipe'] = recipe

        return context

class RecipeEditView(BaseUpdateView):
    model = Recipe
    template_name = 'RecipeBook/edit_recipe.html'
    context_object_name = 'recipe_edit'
    queryset = None
    slug_field = 'slug'
    slug_url_kwarg = 'slug'
    form_class = RecipeForm

    def get_context_data(self, *args, **kwargs):
        context = super(RecipeEditView, self).get_context_data()
        recipe = self.object
        print(recipe.name)
        recipe.ingredients = recipe.ingredients_list.split('\n')
        recipe.categories_list = ""
        categories = Category.objects.filter(recipe=recipe)
        for category in categories:
            if category != categories[-1]:
                recipe.categories_list += (category + ", ")
            else:
                recipe.categories_list += category

        recipe_edit_form = RecipeForm(initial={'name': recipe.name, 'ingredients_list': recipe.ingredients,
                                               'directions': recipe.directions, 'prep_time': recipe.prep_time,
                                               'cook_time': recipe.cook_time, 'servings': recipe.servings,
                                               'source': recipe.source, 'category_input': recipe.categories_list})
        context['recipe'] = recipe
        context['recipe_edit_form'] = recipe_edit_form

        return context

模型.py：

class Recipe(models.Model):
    id = models.AutoField(primary_key=True)
    name = models.CharField(max_length=100, default="")
    ingredients_list = models.TextField(default="")
    servings = models.IntegerField(default=0, null=True, blank=True)
    prep_time = models.IntegerField(default=0, null=True, blank=True)
    cook_time = models.IntegerField(default=0, null=True, blank=True)
    directions = models.TextField(default="")
    source = models.CharField(max_length=100, default="", null=True, blank=True)
    categories = models.ManyToManyField(Category, blank=True)
    slug = models.CharField(max_length=200, default="")

    def __str__(self):
        return self.name

网址.py

# ex: /Recipes/Grilled_Chicken/
    path('Recipes/<slug>/', views.RecipeDetailView.as_view(), name='view_recipe'),
    path('Recipes/<path:slug>/', views.RecipeDetailView.as_view(), name='view_recipe'),
    # ex: /Recipes/edit/Steak/
    path('Recipes/edit/<slug>/', views.RecipeEditView.as_view(), name='edit_recipe'),
    path('Recipes/edit/<path:slug>/', views.RecipeEditView.as_view(), name='edit_recipe'),

recipe_detail.html 中的链接：

<a href="{% url 'RecipeBook:edit_recipe' recipe.slug %}" style="float: right">Edit Recipe</a>

我一直在发疯，试图弄清楚。根据我在这里的所有内容，我在 detailView 中提取的配方应该能够传递给 editView，但是每次我尝试打开 edit_recipe 页面时，它总是告诉我它不能找到指定的配方。它生成的 URL 显示了它应该显示的正确的 slug 和链接。我不知道此时我错过了什么......

标签： pythondjangodjango-urls

python - Django编辑模型实例找不到实例

问题描述

解决方案

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