首页 > 解决方案 > EC P 256 x,y 坐标成公钥?

问题描述

我有 JWT(实际上是 JWK),其中包含

"publicKeySet": {
"keys": [
  {
    "kid": "0",
    "kty": "EC",
    "crv": "P-256",
    "x": "TVRb9i0TUz2JVgfejnYSi-ux8hCjYu2IIvis9ov_i20",
    "y": "ot6nTre05Li6-RW5v36TXnI32-ZUuwTQx5baMXOs5do",
    "x5c": [
      "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",
      "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"
    ]
  },

我需要一个公钥,但我不知道这些信息是否有助于获取 EC 公钥?我需要一个像这样的公钥..

-----BEGIN PUBLIC KEY-----NFkwEwYHKoZIzj0CAQYIKoZIzj0DAQcDQgAECpqQ7EJ3Ba86QIQiA0nn0PPDp2sjJAGXoJt487h1yZOb8UTBC4NqFrFf5Y8zMk1YcyWB0l9jUSNaDLtMwibjJw==-----END PUBLIC KEY-----

是否可以?还有其他获取公钥的方法吗?谢谢

标签: cryptographypublic-keyelliptic-curve

解决方案


是的,您拥有所需的一切。

在椭圆曲线密码学(曲线 P-256)中,公钥只是X,Y定义曲线的笛卡尔平面和有限域上的坐标。

因此,您的公钥是:

"x": "TVRb9i0TUz2JVgfejnYSi-ux8hCjYu2IIvis9ov_i20"

"y": "ot6nTre05Li6-RW5v36TXnI32-ZUuwTQx5baMXOs5do"

这些X,Y值是用 编码的base64,但是请注意_应该用/-替换+(这是因为使用了 URL 安全 base64)。


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