python - 根据产品类别拆分采购订单

Question

我想根据产品类别拆分采购订单。

到目前为止我的代码：

_inherit ='purchase.order.line'  
split = fields.Boolean(string='Split')


_inherit ='purchase.order'
def btn_split_rfq(self):
            flag = []
            for record in self: 
                if record.order_line:
                    for rec in record.order_line:
                        rec.split = True # oles tis eggrafes true
                        flag.append(rec.product_id.categ_id.id) # lista me ta categ ids
                        newlist=[ii for n,ii in enumerate(flag) if ii not in flag[:n]] # ta krata mono mia fora an uparxoun polles
                    for index in newlist: # gia 2 katigories 8a treksi 2 fores
                        quotation_id = self.copy()
                        for index in record.order_line:
                            if index.split:
                                self.env['purchase.order.line'].browse(index.id).unlink() 
                else:
                    raise ValidationError(_('Please Select Order Line To Split'))

到目前为止，代码被拆分为多个 PO，例如，如果我有 2 种类型的类别正在制作 2 个 PO，但是这两个 PO 正在使用，并且 4 种产品不仅属于产品类别（见下图）。

输出：

但我想要这种输出：

有什么解决办法吗？

标签： pythonodooodoo-12

Answer 1

我试图忽略您的代码示例，因为这对我来说很难理解。如果你想试试我的尝试：

def button_split_by_prod_categ(self):
    self.ensure_one()
    groups = {}
    # group lines by product category
    for line in self.order_line:
        if line.product_id.categ_id not in groups:
            groups[line.product_id.categ_id] = line
        else:
            groups[line.product_id.categ_id] =| line
    skip = True
    orders = self
    for lines in groups.values():
        # skip first group
        if skip:
            skip = False
            continue
        # or create a new order without lines and connect
        # the group's lines with it
        else:
            default_values = {'order_line': []}
            new_order = self.copy(default=default_values)
            lines.write({'order_id': new_order.id})
            orders |= new_order
    # now you could return a list view with all orders
    # or just do 'nothing'
    return