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camera - Gstreamer - 示踪子系统 - 如何解释这些措施？

问题描述

我正在学习 Gstreamer。我正在尝试使用 Tracer 子系统，但我不知道如何解释测量结果。

数据：

管道 1：

/opt/vc/bin/raspivid -t 60000 -cd MJPEG -w 426 -h 240 -fps 15 -b 429000 -vf -hf \
-o - | GST_DEBUG="GST_TRACER:7" GST_DEBUG_FILE=240.log GST_TRACERS="latency(flags=pipeline+element+reported)" \
gst-launch-1.0 -v  fdsrc do-timestamp=true ! \
"image/jpeg,width=426,height=240,framerate=15/1,payload=(int)26" ! \
jpegparse ! rtpjpegpay ! \
udpsink port=13000 host=192.168.1.111 && gst-stats-1.0 240.log

测量（管道 1）：

Latency Statistics:
0x20340f0.fdsrc0.src|0x20ff150.udpsink0.sink: mean=0:00:00.001291400 min=0:00:00.000751041 max=0:00:00.007009887

Element Latency Statistics:
0x21040f0.capsfilter0.src: mean=0:00:00.000236961 min=0:00:00.000096875 max=0:00:00.000554530
0x20ec2d0.jpegparse0.src: mean=0:00:00.000558282 min=0:00:00.000346250 max=0:00:00.006139732
0x20f80b8.rtpjpegpay0.src: mean=0:00:00.000458047 min=0:00:00.000248542 max=0:00:00.004859044

Element Reported Latency:
0x20340f0.fdsrc0: min=0:00:00.000000000 max=0:00:00.000000000 ts=0:00:00.644349393
0x21040f0.capsfilter0: min=0:00:00.000000000 max=0:00:00.000000000 ts=0:00:00.644468508
0x20ec2d0.jpegparse0: min=0:00:00.000000000 max=0:00:00.000000000 ts=0:00:00.644528403
0x20f80b8.rtpjpegpay0: min=0:00:00.000000000 max=99:99:99.999999999 ts=0:00:00.644595383

管道 2（rpicamsrc）：

GST_DEBUG="GST_TRACER:7" GST_DEBUG_FILE=240p.log GST_TRACERS="latency(flags=pipeline+element+reported)" \
 gst-launch-1.0 rpicamsrc preview=0 rotation=180 bitrate=4429000 ! \
 image/jpeg,width=1270, height=720,framerate=30 ! \
 jpegparse ! rtpjpegpay ! port=13000 host=192.168.1.111 && gst-stats-1.0 240p.log

测量（管道 2）：

Latency Statistics:
0x485738.rpicamsrc0.src|0x550e98.udpsink0.sink: mean=0:00:00.002029413 min=0:00:00.000996300 max=0:00:00.007922902

Element Latency Statistics:
0x556118.capsfilter0.src: mean=0:00:00.000220204 min=0:00:00.000116354 max=0:00:00.000882290
0x53c2e8.jpegparse0.src: mean=0:00:00.000840342 min=0:00:00.000421510 max=0:00:00.006688112
0x54a0c8.rtpjpegpay0.src: mean=0:00:00.000968794 min=0:00:00.000458436 max=0:00:00.006141604

Element Reported Latency:
0x485738.rpicamsrc0: min=0:00:00.000000000 max=0:00:00.000000000 ts=0:00:00.473207970
0x556118.capsfilter0: min=0:00:00.000000000 max=0:00:00.000000000 ts=0:00:00.473302137
0x53c2e8.jpegparse0: min=0:00:00.000000000 max=0:00:00.000000000 ts=0:00:00.473359064
0x54a0c8.rtpjpegpay0: min=0:00:00.000000000 max=0:00:00.000000000 ts=0:00:00.473419220

我知道在第一个管道中，从相机接收数据流需要644.3 毫秒，而在第二个管道中需要473.2 毫秒。

这种对数据的解释是否正确？如果是这样，为什么需要这么长时间才能获得流量？

干杯。

标签： cameraraspberry-pi3gstreamerraspbiangstreamer-1.0

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