首页 > 解决方案 > 将 UDT 传递给存储过程时出现“值不在预期范围内”

问题描述

这是我到 Oracle 中 UDT 的类映射(非常简单):

[OracleCustomTypeMapping("PORTAL_OPS.SHAPEUDT")]
public class Shape : IOracleCustomType, IOracleCustomTypeFactory
{
 [OracleObjectMapping("SIDES")]
 public Int32 Sides { get; set; }

 public string UdtTypeName
 {
      get
      {
           Attribute attr = Attribute.GetCustomAttribute(this.GetType()
                                    , typeof(OracleCustomTypeMappingAttribute));

           return (attr != null) ?
           ((OracleCustomTypeMappingAttribute)attr).UdtTypeName
            :
           String.Empty;
      }
 }

 public void FromCustomObject(OracleConnection con, IntPtr pUdt)
 {
      OracleUdt.SetValue(con, pUdt, "SIDES", Sides);
 }

 public void ToCustomObject(OracleConnection con, IntPtr pUdt)
 {
      Sides = (int)OracleUdt.GetValue(con, pUdt,"SIDES");
 }

 public IOracleCustomType CreateObject()
 {
      return new Shape();
 }

}

调用存储过程:

 if (Command.Connection.State == ConnectionState.Closed)
 {
      Command.Connection.Open();
 }

 // setting up the parameter
 OracleParameter param = new OracleParameter();
 param.Direction = ParameterDirection.Input;
 param.UdtTypeName = udt.UdtTypeName;
 param.DbType = DbType.Object;
 param.OracleDbType = OracleDbType.Object;
 param.Value = udt;


 Command.CommandText = "PORTAL_OPS.PROC_CREATE_SHAPE";
 Command.CommandType = CommandType.StoredProcedure;
 Command.Parameters.Add(param);
 Command.ExecuteNonQuery();

实例化:

Shape shape = new Shape();
shape.sides = 4;
//invoking the stored procedure call (see code above)

我无法弄清楚为什么我不断收到“价值不在预期范围内”。整个周末都在看这个……运气不好。任何帮助是极大的赞赏。

标签: c#oraclestored-proceduresuser-defined-typesodp.net-unmanaged

解决方案


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