首页 > 解决方案 > 使用 Oracle SQL 将重复计数连接到现有子查询

问题描述

我被要求构建一个查询,对某个状态测试的数据运行质量检查。

我有以下查询,它创建一个名为“标志”的变量来识别存在问题的情况。主查询实际上是在子查询中,我通过仅选择 Flag 具有值的情况来过滤掉没有标志的所有记录。

对于有重复测试的情况,我希望能够有一个 CASE WHEN。我们确实有一些重复项,对于相同的学生 ID(test.studentID、studenttestscore.studentID、students.ID),学生将在同一考试中具有相同的考试日期。

如您所见,测试日期是 STUDENTTEST.TEST_DATE。可以通过 STUDENTTEST.ID 或 TEST.NAME 识别考试。对于 STUDENTTEST.studentID,查找 STUDENTTEST.test_date 和 STUDENTTEST.ID 相同的记录可能更容易。但是一旦你得到这个计数,它就必须被附加到这里的子查询中,这样我们就可以有一个与之关联的学生姓名。

with query as (select STUDENTS.STUDENT_NUMBER as "Student ID", Students.Lastfirst as "Student Name",
    STUDENTS.GRADE_LEVEL as "Current Grade Level",
    TEST.NAME as "Test Name",
    STUDENTTEST.GRADE_LEVEL as "Grade level at time of exam",
    STUDENTTEST.TEST_DATE as TEST_DATE,
    STUDENTTESTSCORE.NUMSCORE as Score, STUDENTTESTSCORE.PERCENTSCORE as PCTScore,
S_NY_STU_X.DATEOFENTRYGRade9 as Cohort,
CASE
WHEN STUDENTTEST.GRADE_LEVEL <9 or STUDENTTEST.GRADE_LEVEL>12 then 'Invalid Grade Level'
WHEN STUDENTTESTSCORE.NUMSCORE != STUDENTTESTSCORE.PERCENTSCORE then 'Mismatch between number and percent score'
WHEN TEST.NAME like '% - T%' then 'Transitional Global no longer administered'
WHEN STUDENTTEST.TEST_DATE>CURRENT_DATE THEN 'Test date invalid'
WHEN STUDENTTESTSCORE.NUMSCORE <0 THEN 'Test score out of range'
WHEN STUDENTTESTSCORE.NUMSCORE <0 THEN 'Test score out of range'
WHEN STUDENTTESTSCORE.NUMSCORE >100  THEN 'Test score out of range'
WHEN STUDENTTESTSCORE.PERCENTSCORE > 100 THEN 'Test score out of range'
END AS Flag
 from STUDENTS STUDENTS,
    STUDENTTEST STUDENTTEST,
    STUDENTTESTSCORE STUDENTTESTSCORE,
    TEST TEST,
    TESTSCORE TESTSCORE,
    S_NY_STU_X S_NY_STU_X

 where 
 Test.Name like 'Regents%' and
 STUDENTTESTSCORE.TESTSCOREID=TESTSCORE.ID
    and STUDENTTESTSCORE.STUDENTTESTID=STUDENTTEST.ID
    and STUDENTTESTSCORE.STUDENTID=STUDENTTEST.STUDENTID
    and STUDENTS.ID=STUDENTTEST.STUDENTID
    and STUDENTS.ID=STUDENTTESTSCORE.STUDENTID
    and STUDENTTEST.TESTID=TEST.ID
and S_NY_STU_X.STUDENTSDCID=STUDENTS.DCID)
select * from query where flag is not null 

太感谢了!!

标签: sqloracleoracle11goracle-apex

解决方案


据我了解,您可以将此分析添加count()到您的case

when count(1) over (partition by studenttest.test_date, 
                                 studenttest.id, 
                                 studenttest.studentid) > 1 
then 'duplicate'

这是示例:

with t (test_date, test_id, student_id) as (
    select date '2013-05-18', 707, 20214 from dual union all
    select date '2013-05-18', 707, 20214 from dual union all
    select date '2013-05-12', 707, 20214 from dual union all
    select date '2023-05-18', 707,  1003 from dual union all
    select date '2013-05-02', 705,  1003 from dual )
select t.*, 
       case 
            when test_date > current_date 
            then 'Test date invalid'
            when count(1) over (partition by test_date, test_id, student_id) > 1 
            then 'duplicated test' 
       end as flag
  from t

结果:

TEST_DATE      TEST_ID STUDENT_ID FLAG
----------- ---------- ---------- -----------------
2013-05-02         705       1003 
2013-05-12         707      20214 
2013-05-18         707      20214 duplicated test
2013-05-18         707      20214 duplicated test
2023-05-18         707       1003 Test date invalid

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