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c# - C# XML 解析双标签以列出

问题描述

我有个问题。我有以下类将我的 XML 解析为：

[XmlRoot(ElementName = "picture")]
public class SetPicture
{
    [XmlElement(ElementName = "id")]
    public string Id { get; set; }
    [XmlElement(ElementName = "name")]
    public string Name { get; set; }
    [XmlElement(ElementName = "size")]
    public string Size { get; set; }
    [XmlElement(ElementName = "price")]
    public string Price { get; set; }
    [XmlElement(ElementName = "quantity")]
    public string Quantity { get; set; }
    [XmlElement(ElementName = "sizes")]
    public List<Size> Sizes { get; set; }
    [XmlIgnore]
    public ImageSource imageSource { get; set; }
}

[XmlRoot(ElementName = "set")]
public class Set
{
    [XmlElement(ElementName = "name")]
    public string Name { get; set; }
    [XmlElement(ElementName = "price")]
    public string Price { get; set; }
    [XmlElement(ElementName = "pictures")]
    public List<SetPicture> Pictures { get; set; }
}

[XmlRoot(ElementName = "sets")]
public class Sets
{
    [XmlElement(ElementName = "set")]
    public List<Set> Set { get; set; }
}

[XmlRoot(ElementName = "data")]
public class Data
{
    [XmlElement(ElementName = "sets")]
    public Sets Sets { get; set; }
}

我收到以下 XML：

<data>
   <sets>
      <set>
         <name>Set A</name>
         <price>13.9</price>
         <pictures>
            <picture>
               <id>4</id>
               <name>Potret2.jpg</name>
               <size>13 x 18 mat</size>
               <price>6.95</price>
               <quantity>2</quantity>
            </picture>
            <picture>
               <id>5</id>
               <name>Potret2Pasfoto.jpg</name>
               <size>13 x 18 mat</size>
               <price>6.95</price>
               <quantity>1</quantity>
            </picture>
         </pictures>
      </set>
   </sets>
</data>

但是在将 XML 解析为 Class 之后，我得到一个空的List<SetPicture> Pictures. 我想我知道出了什么问题，因为我将标签解析<pictures>到列表中，但我需要将元素解析<picture>到列表中。

我怎样才能解决这个问题？

标签： c#xmlparsing

解决方案

方法 1 - 更改Set类。创建Pictures具有列表的新类Picture

[XmlRoot(ElementName = "set")]
public class Set
{
    [XmlElement(ElementName = "name")]
    public string Name { get; set; }
    [XmlElement(ElementName = "price")]
    public string Price { get; set; }
    [XmlElement(ElementName = "pictures")]
    public Pictures Pictures { get; set; }
}

[XmlRoot(ElementName = "pictures")]
public class Pictures
{
    [XmlElement(ElementName = "picture")]
    public List<SetPicture> Picture { get; set; }
}

方法 2 - 更改XmlElement为XmlArray

[XmlRoot(ElementName = "set")]
public class Set
{
    [XmlElement(ElementName = "name")]
    public string Name { get; set; }
    [XmlElement(ElementName = "price")]
    public string Price { get; set; }
    [XmlArray("pictures")]
    [XmlArrayItem("picture", typeof(SetPicture))]
    public List<SetPicture> Pictures { get; set; }
}

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