python - 如何将列表从一个函数传递到另一个函数？

Question

问题：玩弄在函数之间交换变量的想法。

我正在执行以下代码：

def benefits():
    list =  ["Beautiful", "Explicit", "Simple", "Readability","Easy to share"]
    return list

def statement(benefit):
    print("The benifit is " + benefit )          


def benefits_of_functions():  
    benefits_list = benefits()
    for benefit in benefits_list:
        print(statement(benefit))


benefits_of_functions()

我得到错误：

The benifit is Beautiful
None
The benifit is Explicit
None
The benifit is Simple
None
The benifit is Readability
None
The benifit is Easy to share
None

我无法理解“无”。你能帮我弄清楚为什么会出现在输出中吗？

标签： pythonpython-3.xlistfunction

Answer 1

在函数中返回而不是打印statement：

def benefits():
    list =  ["Beautiful", "Explicit", "Simple", "Readability","Easy to share"]
    return list

def statement(benefit):
    return "The benifit is " + benefit


def benefits_of_functions():  
    benefits_list = benefits()
    for benefit in benefits_list:
        print(statement(benefit))


benefits_of_functions()