首页 > 解决方案 > WPF 中的井字游戏 GUI

问题描述

所以我有点情况,我需要在单击按钮时弹出一个 X 或 O,但它不想接受 button.Text、button.TextMenu、button.DataContent 或 button.ContextMenu。我该怎么办?我也在关注一个旧视频,所以我不知道他们是否改变了它。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
using System.Threading;

namespace ticTacToeGui
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();

        }

        public int player = 2;
        public int turns = 0;
        public int s1 = 0;
        public int s2 = 0;
        public int sd = 0;


        private void Button_Click(object sender, RoutedEventArgs e)
        {
            Button button = (Button)sender;
            if(player%2==0)
            {
                button.DataContext = "X";
                player++;
                turns++;
            }
            else
            {
                button.DataContext = "O";
                player++;
                turns++;
            }
        }

继续...

标签: c#

解决方案


您需要使用 Button 的 Content 属性。

   private void Button_Click(object sender, RoutedEventArgs e)
    {
        Button button = (Button)sender;
        if(player%2==0)
        {
            button.Content = "X";
            player++;
            turns++;
        }
        else
        {
            button.Content= "O";
            player++;
            turns++;
        }
    }

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