首页 > 解决方案 > 为什么以下类型声明和/或实例化在 Julia 1.0 中不起作用?

问题描述

我有一个圆圈类型

struct Circle{T <: Real}
  # radius is a subtype of
  # the real number approximation types
  R::T
  # The center is a named pair of real
  # number approximation types
  C::NamedTuple{T, T}
end

我想用它来实例化

circles = NamedTuple(
    A = Circle(1, ( 1,  1)),
    B = Circle(1, ( 2,  2))
  )

产生错误

ERROR: LoadError: MethodError: no method matching Circle(::Int64, ::Tuple{Int64,Int64})
Closest candidates are:
  Circle(::T<:Real, ::NamedTuple{T<:Real,T<:Real}) where T<:Real

为什么会发生此错误,我做错了什么?

标签: typestype-conversionjuliatype-constructor

解决方案


命名元组由名称和元组参数化:

julia> struct Circle{T <: Real}
         R::T
         C::NamedTuple
         Circle(r::T, c::NamedTuple{N,Tuple{T,T}}) where {N, T <: Real} = new{T}(r,c)
       end

julia> Circle(1, (a=1, b=2))
Circle{Int64}(1, (a = 1, b = 2))

如果你想Circle用一个元组构造一个,你可以提供一个默认映射:

julia> function Circle(r::T, c::Tuple{T,T}) where {T <: Real}
           a, b = c
           return Circle(r, (a=a, b=b))
       end
Circle

julia> Circle(1, (1, 2))
Circle{Int64}(1, (a = 1, b = 2))

如果您不需要命名元组,则可以使用常规元组:

julia> struct Circle{T <: Real}
         R::T
         C::Tuple{T, T}
       end

julia> Circle(1, (1, 2))
Circle{Int64}(1, (1, 2))

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