首页 > 解决方案 > Python 属性错误:“int”对象没有属性“reshape”

问题描述

我正在尝试使用 python 预测股票价格,同时尝试将数据集重塑为“fit”函数的 2D num 数组,并以此为参考:sklearn Logistic Regression "ValueError: Found array with dim 3. Estimator expected <= 2 。”

next_day_open_values, nx, ny = next_day_open_values.shape
next_day_open_values = next_day_open_values.reshape((next_day_open_values,nx*ny))
y_normaliser = preprocessing.MinMaxScaler()
y_normaliser.fit((np.expand_dims( next_day_open_values, -1 )))

我遇到了这个错误:

    <ipython-input-42-6ea43c55dc18> in csv_to_dataset(csv_path)
     20 
     21     next_day_open_values, nx, ny = next_day_open_values.shape
---> 22     next_day_open_values = next_day_open_values.reshape((next_day_open_values,nx*ny))
     23     y_normaliser = preprocessing.MinMaxScaler()
     24     y_normaliser.fit((np.expand_dims( next_day_open_values, -1 )))

AttributeError: 'int' object has no attribute 'reshape'

出了什么问题?我该如何解决?详细的答案表示赞赏。

到目前为止的代码如下(我使用的是 Jupyter notebook):

import keras
from keras.models import Model
from keras.layers import Dense, Dropout, LSTM, Input, Activation
from keras import optimizers
import numpy as np
np.random.seed(4)
import tensorflow
tensorflow.random.set_seed(4)
import pandas as pd
from sklearn import preprocessing
import numpy as np

history_points = 50

def csv_to_dataset(csv_path):
    data = pd.read_csv(csv_path)
    data = data.drop('Date', axis=1)
    data = data.drop(0, axis=0)
    data_normaliser = preprocessing.MinMaxScaler()
    data_normalised = data_normaliser.fit_transform(data)
    # using the last {history_points} open high low close volume data points, predict the next open value
    ohlcv_histories_normalised =      np.array([data_normalised[i  : i + history_points].copy() for i in range(len(data_normalised) - history_points)])
    next_day_open_values_normalised = np.array([data_normalised[:,0][i + history_points].copy() for i in range(len(data_normalised) - history_points)])
    next_day_open_values_normalised = np.expand_dims(next_day_open_values_normalised, -1)

    next_day_open_values = np.array([data.iloc[:,0][i + history_points].copy() for i in range(len(data) - history_points)])
    next_day_open_values = np.expand_dims(next_day_open_values_normalised, axis=-1)

    next_day_open_values, nx, ny = next_day_open_values.shape
    next_day_open_values = next_day_open_values.reshape((next_day_open_values,nx*ny))
    y_normaliser = preprocessing.MinMaxScaler()
    y_normaliser.fit((np.expand_dims( next_day_open_values, -1 )))

    assert ohlcv_histories_normalised.shape[0] == next_day_open_values_normalised.shape[0]
    return ohlcv_histories_normalised, next_day_open_values_normalised, next_day_open_values, y_normaliser
#dataset
hlcv_histories, next_day_open_values, unscaled_y, y_normaliser = csv_to_dataset('AMZN1.csv')

test_split = 0.9 # the percent of data to be used for testing
n = int(ohlcv_histories.shape[0] * test_split)

# splitting the dataset up into train and test sets

ohlcv_train = ohlcv_histories[:n]
y_train = next_day_open_values[:n]

ohlcv_test = ohlcv_histories[n:]
y_test = next_day_open_values[n:]

unscaled_y_test = unscaled_y[n:]

随意更正/编辑这个。

谢谢

标签: pythonnumpytensorflowkeras

解决方案


您提供了大量的代码行,但这实际上归结为一个问题:您正在从next_day_open_values, nx, ny = next_day_open_values.shape. Numpy 的 reshape 需要一个数组作为输入,而不是整数或单个值。

参数:numpy.reshape(a, newshape, order='C')

a : array_like - 要重塑的数组。

我怀疑你是否试图获得一个重复nx*ny形状的单个整数的向量。此外,如果您将输入转换为数组,并执行相同的操作,您会遇到,ValueError因为您无法将大小为 1 的数组重新整形为特定形状。

我相信这可能有效,但我不知道是什么next_day_open_values

next_day_open_values_s, nx, ny = next_day_open_values.shape
next_day_open_values = next_day_open_values.reshape(next_day_open_values_s,nx*ny)

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