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javascript - Scrapy 只抓取前两页

问题描述

我正在尝试抓取一个网站，但需要在所有页面中使用 splash，因为它们的内容是动态创建的。现在它只呈现前 2 页，尽管总共有 47 页。

这是代码：

import scrapy
from scrapy.http import Request
from scrapy_splash import SplashRequest

class JobsSpider(scrapy.Spider):
    name = 'jobs'
    start_urls = ['https://jobs.citizensbank.com/search-jobs']

    def start_requests(self):
        filters_script = """function main(splash)
                                assert(splash:go(splash.args.url))
                                splash:wait(3)
                                return splash:html()
                            end"""

        for url in self.start_urls:
            yield SplashRequest(url=url,
                                callback=self.parse,
                                endpoint='execute',
                                args={'lua_source': filters_script})

    def parse(self, response):
        cars_urls = response.xpath('.//section[@id="search-results-list"]/ul/li/a/@href').extract()
        for car_url in cars_urls:
            absolute_car_url = response.urljoin(car_url)
            yield scrapy.Request(absolute_car_url,
                          callback=self.parse_car)

        script_at_page_1 = """function main(splash)
                                assert(splash:go(splash.args.url))
                                splash:wait(3)

                                next_button = splash:select("a[class=next]")
                                next_button.mouse_click()
                                splash:wait(3)
                                return {
                                    url = splash:url(),
                                    html = splash:html()
                                }
                            end"""

        script_at_page_2 = """function main(splash)
                                assert(splash:go(splash.args.url))
                                splash:wait(3)

                                next_button = splash:select("a[class=next]")
                                next_button.mouse_click()
                                splash:wait(3)
                                return {
                                    url = splash:url(),
                                    html = splash:html()
                                }
                            end"""

        script = None
        if response.url is not self.start_urls[0]:
            script = script_at_page_2
        else:
            script = script_at_page_1

        yield SplashRequest(url=response.url,
                            callback=self.parse,
                            endpoint='execute',
                            args={'lua_source': script})


    def parse_car(self, response):
        jobtitle = response.xpath('//h1[@itemprop="title"]/text()').extract_first()
        location = response.xpath('//span[@class="job-info"]/text()').extract_first()
        jobid = response.xpath('//span[@class="job-id job-info"]/text()').extract_first()

        yield {'jobtitle': jobtitle,
                'location': location,
                'jobid': jobid}

我已经以我能想到的各种方式玩了它，但它没有用。我是scrapy的新手，所以任何帮助表示赞赏。

标签： javascriptscrapyscrapy-splash

解决方案

我认为您不需要为此使用 Splash。如果您查看浏览器检查器的网络选项卡，您会看到它正在向 XHR 下的此 URL 发出请求：

https://jobs.citizensbank.com/search-jobs/results?ActiveFacetID=0&CurrentPage=3&RecordsPerPage=15&Distance=50&RadiusUnitType=0&Keywords=&Location=&Latitude=&Longitude=&ShowRadius=False&CustomFacetName=&FacetTerm=&FacetType=0&SearchResultsModuleName=Search+Results&SearchFiltersModuleName=Search+过滤器&SortCriteria=0&SortDirection=0&SearchType=5&CategoryFacetTerm=&CategoryFacetType=&LocationFacetTerm=&LocationFacetType=&KeywordType=&LocationType=&LocationPath=&OrganizationIds=&PostalCode=&fc=&fl=&fcf=&afc=&afl=&afcf=

尝试向此 URL 发出请求并每次更改页面。如果您遇到问题，您可能需要查看 XHR 请求的标头并复制它们。如果您单击该链接，JSON 将加载到您的浏览器中。因此，只需将第 1 页设置为您的 start_url 并覆盖 start_requests，如下所示：

start_urls = ['https://jobs.citizensbank.com/search-jobs/results?ActiveFacetID=0&CurrentPage={}&RecordsPerPage=15&Distance=50&RadiusUnitType=0&Keywords=&Location=&Latitude=&Longitude=&ShowRadius=False&CustomFacetName=&FacetTerm=&FacetType=0&SearchResultsModuleName=Search+Results&SearchFiltersModuleName=Search+Filters&SortCriteria=0&SortDirection=0&SearchType=5&CategoryFacetTerm=&CategoryFacetType=&LocationFacetTerm=&LocationFacetType=&KeywordType=&LocationType=&LocationPath=&OrganizationIds=&PostalCode=&fc=&fl=&fcf=&afc=&afl=&afcf=']

def start_requests(self):
    num_pages = 10
    for page in range(1, num_pages):
        yield scrapy.Request(self.start_urls[0].format(page), callback=self.parse)

还值得注意的是，您可以设置 RecordsPerPage 设置。您可以将其设置得更高，并可能在一页上获取所有记录，或者减少获取所有记录的请求。

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