regex - 如何拆分作为编号列表的字符串

Question

我有一个这样的字符串

20. Kyoto, Japan19. Rijeka, Croatia18. Panama17. Rabat, Morocco16. The British Virgin Islands15. Frisian Islands, Denmark14. Qingdao, China13. Lebanon12. Portland, Maine, US11. Dakar, Senegal10. Egadi Islands, Sicily9. Paris, France8. Siargao, Philippines7. Galway, Ireland6. Kangaroo Island, Australia5. Salvador, Brazil4. Armenia3. Kyrgyzstan2. Plymouth, UK1. Pakistan19. THE TURKISH RIVIERA18. PERTH, WESTERN AUSTRALIA17. SINGAPORE16. THE SCOTTISH HIGHLANDS15. St Barth’s,Caribbean14. Mozambique13. Mumbai12. The Peloponnese, Greece11. Tahiti10. Namibia9. Patagonia8. Arles, France7. Chengdu, China6. Egypt5. Transylvania, Romania4. TASMANIA, AUSTRALIA3. New Orleans2. Valle de Guadalupe1. Matera, Italy

我将如何按列表编号拆分它？可以这样做保留数字还是我最好稍后添加数字？

标签： regexrubysplit

Answer 1

如果您确信除了项目编号之外没有数字，这很容易。String#scan对于数字→ <em>点 →空格→ <em>不是数字。

str.scan(/(\d+)\.\s+(\D+)/)
#⇒ [["20", "Kyoto, Japan"],
#   ["19", "Rijeka, Croatia"],
#   ["18", "Panama"],
#   ["17", "Rabat, Morocco"]
#   ....]