if-statement - 脚本如果然后在两张纸之间匹配

Question

我想要做的是把这个公式=iferror(if(match($A2&F$1,arrayformula(Transpose!B$3:B&Transpose!B$1),0),"P"),"")变成谷歌表格的脚本。本质上，该公式在 F 之后的每隔一列和 2 下的每一行中运行。

例如在 HI 列有 =iferror(if(match($A2&H$1,arrayformula(Transpose!C$3:C&Transpose!C$1),0),"P"),"")

在列姬有=iferror(if(match($A2&J$1,arrayformula(Transpose!D$3:D&Transpose!D$1),0),"P"),"") 等。我现在的方式是将这个公式粘贴到其他每一列的每个单元格中，当我添加更多数据时，我必须调整公式，所以它需要太长时间。我已经附上了工作簿，所以你可以看到我在说什么。任何帮助，将不胜感激。谢谢

https://docs.google.com/spreadsheets/d/1ZBrg4XoeL21mXwn93XT35kgjrE5pqx9cd3xEvfojIXM/edit?usp=sharing

我努力了

  var ss=SpreadsheetApp.getActive().getSheetByName('Transpose')
  var Ts=SpreadsheetApp.openById('1ZBrg4XoeL21mXwn93XT35kgjrE5pqx9cd3xEvfojIXM').getSheetByName('Attendance')
  var meeting = ss.getRange("B3:B37").getValues();
  var targetNames = Ts.getRange("A2:A37").getValues();
  var writtingRange = Ts.getRange("F2:F37").getValues();
  var updatedUser = targetNames;
  var writtingColumn = -1;
  var coolMatrix;

  for (var i = 0; i < meeting.length; i++) {
    var name = meeting[i][0]
    for (var j = 0; j < targetNames.length; j++) {
      if (targetNames[j][0] == name) {
        for (var z = 0; z < writtingRange[0].length; z++) {
          if (writtingRange[j][z] == '' && writtingColumn < 0) {
            writtingColumn = z;
            break;
          }
        }
        writtingRange[j][writtingColumn] = meeting[i][1];
        updatedUser[j] = true;
      }
    }
  }
  Ts.getRange("F2:F37").setValues(writtingRange);
}

但它给了我名称匹配的空白和名称不匹配的未定义“未定义”我也知道这个脚本只适用于一列而不是其他每一列。

标签： if-statementgoogle-apps-scriptmatch

Answer 1

我对工作表名称中的空格有疑问。这是因为=transpose(split(B2,","))，它将每个列表拆分为分隔名称,。问题是 coma 后面有一个空格，它会混淆名称之间的比较。当名称位于第一个位置时，它没有空格，但如果它位于另一个列表的另一个位置，它就会有。

我通过再次获取每个列表并进行替换以删除每个名称的第一个空格来解决此问题。此外，您应该删除工作表与会者列表中每个姓名的第一个空格。

function myfunction() {

  var sprsheet = SpreadsheetApp.getActiveSpreadsheet();
  var transpose = sprsheet.getSheetByName("Transpose");
  var attendance = sprsheet.getSheetByName("Attendance");

  //Ranges of Transpose
  var colDates = transpose.getRange("B1:I1").getValues();
  var attendees = transpose.getRange("B2:I2").getValues();

  //Ranges of Attendance
  var eventsCol = ["F","H","J","L","N","P","R","T"]; //The dates of Transpose are different from the ones in Attendance, so I added "T" so the script doesn't broke.
  var kids = attendance.getRange("A2:A17").getValues(); //Increase this if you add more names ("Abraham Paz" was missing from this list)

  loop1:
  for (var i = 0; i < eventsCol.length; i++){ //For each column 

    var list = getIndividuals(attendees[0][i]); //Get the list of each Transpose row 2

    loop2:
    for (var x = 0; x < kids.length; x++){ //For each name in Attendance

      loop3:
      for (var y = 0; y < list.length; y++){ //Compare it with each name of the list

        if (list[y] == kids[x][0] || list[y] == " " + kids[x][0]){ //Second "or" is in case there is an space in the first position.

          attendance.getRange(eventsCol[i]+(x+2)).setValue("P");
          break loop3; //Once it finds a name it makes no sense to keep searching. Go back to the next name.

        } 

      }

    }
  }

}
//Split the list into each name, removing the first space
function getIndividuals(attendees){

  var individuals = attendees.split(",");

  for (var i = 0; i < individuals.length; i++){ 

    if (individuals[i][0] == " "){

      individuals[i][0].replace(" ", "");

    }

  }

  return individuals;
}

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结果