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swift - 可编码的 [String: Any] 字典

问题描述

在我的代码中，我有一个具有 type 属性的类[String: Any]。在实现Codable协议时，编译器显示错误，说

Protocol type 'Any' cannot conform to 'Decodable' because only concrete types can conform to protocols

open class MMSDKNotification: Codable {

    enum MMSDKNotificationKeys: String, CodingKey { // declaring our keys
        case id = "id"
        case message = "message"
        case isRead = "isRead"
        case creationTime = "creationTime"
    }

    public var id: Int = 0
    public var message: [String: Any]?
    public var isRead: Bool = false
    public var creationTime: Int = 0

    required public init(from decoder: Decoder) throws {
        let container = try decoder.container(keyedBy: MMSDKNotificationKeys.self) // defining our (keyed) container

        self.id = try container.decode(Int.self, forKey: .id)

        // Here is the error:
        // Protocol type 'Any' cannot conform to 'Decodable' because only concrete types can conform to protocols

        self.message = try container.decode(String.self, forKey: .type)

        self.isRead = try container.decode(Bool.self, forKey: .isRead)
        self.creationTime = try container.decode(Int.self, forKey: .creationTime)

    }

    public func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: MMSDKNotificationKeys.self)

        try container.encode(id, forKey: .id)
        try container.encode(isRead, forKey: .isRead)
        try container.encode(creationTime, forKey: .creationTime)
    }
}

可以Codable和[String: Any]字典一起使用吗？

标签： swiftcodable

解决方案

是否可以将 Codable 与 [String: Any] 字典一起使用？

不，您不能使用 Codable，但您可以在新模型中制作这本字典。

代替

公共变量消息：[字符串：任何]？

和

公共变量消息：MessageModel？

struct MessageModel: 可编码 { }

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