javascript - 提交前如何确认一切是否有效?
问题描述
我有一个 HTML5 表单,我正在使用 javascript 来验证表单。
我有几个'if' 检查表单,如果它有效,他们将变量('pass')更改为 true 或 false。它们还显示错误消息。问题是,即使只有一件事是有效的,它也会改变变量为真,我需要它只在其他一切都有效的情况下才让 pass 为真。
我的 HTML:
<!DOCTYPE html>
<html>
<head>
<title>Register</title>
</head>
<body>
<div>
<form name="register" action="register.php" method="POST" >
<label>First Name:</label>
<input type="text" id="firstName" name="firstName"><br />
<label id="warning_first"></label>
<br />
<label>Surname:</label>
<input type="text" id="lastName" name="lastName"><br />
<label id="warning_second"></label>
<br />
<label>Gender:</label>
<input type="radio" name="gender" value="Male" id="male">Male
<input type="radio" name="gender" value="Female">Female
<input type="radio" name="gender" value="Other">Other
<input type="radio" name="gender" value="Prefer not to say"> Prefer not to say <br />
<label id="warning_third"></label>
<br />
<label>Email:</label>
<input type="email" id="email" name="email"> <br />
<label id="warning_fourth"></label>
<br />
<label>Confirm Email:</label>
<input type="email" id="confirmEmail" name="confirmEmail">
<br />
<label>Mobile:</label>
<input type="tel" id="mobileNumber" name="mobileNumber">
<br />
<label>Telephone:</label>
<input type="tel" id="telephoneNumber" name="telephoneNumber">
<br />
<input type="button" id="cancel" name="cancel" value="Cancel" onclick="cancel();">
<input type="button" name="submit" value="Register" onclick="submitCheck();">
</form>
<script src="script.js"></script>
</div>
</body>
</html>
我的 JavaScript:
function submitCheck() {
var pass = false;
var firstName = document.getElementById("firstName").value;
var lastName = document.getElementById("lastName").value;
var genderTest = document.getElementsByName("gender");
var genderIf = false;
for (var a = 0; a < genderTest.length; a += 1) {
if (genderTest[a].checked) {
genderIf = true;
}
}
var emailCheck = document.getElementById("email").value;
if (firstName.length > 0) {
document.getElementById("warning_first").innerHTML = "";
pass = true;
} else {
document.getElementById("warning_first").innerHTML = "This is required!";
pass = false;
}
if (lastName.length > 0) {
document.getElementById("warning_second").innerHTML = "";
pass = true;
} else {
document.getElementById("warning_second").innerHTML = "This is required!";
pass = false;
}
if (genderIf) {
document.getElementById("warning_third").innerHTML = "";
pass = true;
} else {
document.getElementById("warning_third").innerHTML = "This is required!"
pass = false;
}
if (emailCheck.length > 0) {
document.getElementById("warning_fourth").innerHTML = "";
pass = true;
} else {
document.getElementById("warning_fourth").innerHTML = "Your email is too short!";
pass = false;
}
if (pass) {
console.log("OK");
} else {
console.log("NO");
}
}
如您所见,如果电子邮件为真,则控制台将记录“OK”(我用它来查看一切是否有效)。我该如何解决这个问题,以便它不会“传递”为真,如果只是电子邮件有效吗?
由于@onsubmit 的问题,我使用的是普通按钮而不是提交按钮。
解决方案
目前,如果任何元素通过测试,您默认并将其更改为pass
。false
true
颠倒你的逻辑。
将默认值设置pass
为true
。false
如果任何元素未通过测试,请将其更改为。