首页 > 解决方案 > 构造时的 java.time.temporal.ValueRange 错误

问题描述

我正在处理项目中的一些时间问题,并且在实施单元测试时,我不确定我是否发现了错误,或者我是否误解了文档。状态的javadocs ValueRange.of(long min, long maxSmallest, long maxLargest)

 * @return the ValueRange for min, smallest max, largest max, not null
 * @throws IllegalArgumentException if
 *     the minimum is greater than the smallest maximum,
 *  or the smallest maximum is greater than the largest maximum

我读到的方式是,如果传递给 min 的值大于 maxSmallest 的值,它应该抛出异常。但是,以下代码有效:

ValueRange vr = ValueRange.of(5, 2, 10);

我认为这应该失败。min 的值大于 minimum 的最大值,但不抛出异常。另外,打印生成的ValueRange时,看起来很奇怪: 5 - 2/10

这是一个错误吗?还是我只是不理解 javadocs?

标签: java

解决方案


这是一个错误JDK-8239520,它已在 JDK 15 Build 12中修复

我已经为不同的值范围创建了基于ValueRange.of() API 的单元测试:

package org.mycompany.mavenproject1;

import java.time.temporal.ValueRange;
import static org.junit.jupiter.api.Assertions.assertThrows;
import org.junit.jupiter.api.function.Executable;
import org.junit.jupiter.params.ParameterizedTest;
import org.junit.jupiter.params.provider.CsvSource;

public class ValueRangeTest {

    @ParameterizedTest
    @CsvSource({
        "5, 2" // the minimum is greater than the maximum
    })
    public void testFixedValueRange(long min, long max) {
        Executable when = () -> ValueRange.of(min, max);

        assertThrows(IllegalArgumentException.class, when,
                () -> "min: " + min + ", max: " + max);
    }

    @ParameterizedTest
    @CsvSource({
        "5, 2, 10", // the minimum is greater than the smallest maximum - THIS FAILS!
        "2, 10, 2" // the smallest maximum is greater than the largest maximum
    })
    public void testVariableValueRange(long min, long maxSmallest, long maxLargest) {
        Executable when = () -> ValueRange.of(min, maxSmallest, maxLargest);

        assertThrows(IllegalArgumentException.class, when,
                () -> "min: " + min + ", maxSmallest: " + maxSmallest + ", maxLargest: " + maxLargest);
    }

    @ParameterizedTest
    @CsvSource({
        "5, 1, 2, 10", // the smallest minimum is greater than the smallest maximum
        "1, 2, 10, 2", // the smallest maximum is greater than the largest maximum
        "1, 11, 2, 10" // the largest minimum is greater than the largest maximum
    })
    public void testFullyVariableValueRange(long minSmallest, long minLargest, long maxSmallest, long maxLargest) {
        Executable when = () -> ValueRange.of(minSmallest, minLargest, maxSmallest, maxLargest);

        assertThrows(IllegalArgumentException.class, when,
                () -> "minSmallest: " + minSmallest + ", minLargest: " + minLargest + ", maxSmallest: " + maxSmallest + ", maxLargest: " + maxLargest);
    }

}

所有场景都通过了,但只有一个——if the minimum is greater than the smallest maximum

Tests run: 6, Failures: 1, Errors: 0, Skipped: 0, Time elapsed: 0.087 s <<< FAILURE! - in org.mycompany.mavenproject1.ValueRangeTest
testVariableValueRange{long, long, long}[1]  Time elapsed: 0.034 s  <<< FAILURE!
org.opentest4j.AssertionFailedError: min: 5, maxSmallest: 2, maxLargest: 10 ==> Expected java.lang.IllegalArgumentException to be thrown, but nothing was thrown.
    at org.mycompany.mavenproject1.ValueRangeTest.testVariableValueRange(ValueRangeTest.java:30)

这让我相信这是ValueRange.


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