python - 为什么 int2word 程序只打印前十行？

Question

我正在导入一个文件，字数从一到九十九。目标是读取每一行并返回一个与文件中的单词对应的整数值。但是，我似乎无法弄清楚为什么我的代码只适用于前十个数字/行？

def word_to_int(w):
  i = 0  

  ones = [[1,'one'], [2,'two'], [3,'three'], [4,'four'], [5,'five'], [6,'six'], [7,'seven'], [8,'eight'], [9,'nine']]

  teens = [[10,'ten'], [11,'eleven'], [12,'twelve'], [13,'thirteen'], [14,'fourteen'], [15,'fifteen'], [16,'sixteen'], [17,'seventeen'], [18,'eighteen'],[19,'nineteen']]

  tens = [[2,'twenty'], [3,'thirty'], [4,'forty'], [5,'fifty'], [6,'sixty'], [7,'seventy'], [8,'eighty'], [9,'ninety']]

  if(w.find ('-') != -1): 
    a = w.split('-')                          #gets rid of hyphen and seperates parts
    for first in tens:
      if(a[0] == first[1]):                   #first half of word
        i = first[0]*10
    for second in ones:
      if (a[1] == second[1]):                 #second half of word
        i += second[0]

  else:
    for num in ones:
      if w == num[1]:
        i = num[0]

  if(i == 0):
    for num2 in teens:
      if w == num2[1]:
        i == num2[0]

  if(i == 0):
    for num3 in tens:
      if w == num3[1]:
        i = num3[0]*10
    return i    

有任何想法吗？

标签： pythonfunction

Answer 1

请更改如下代码：

if(i == 0):
    for num2 in teens:
        if w == num2[1]:
            i = num2[0]   # not i == num2[0]
            print(num2)

谢谢