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python - views.py 中的“SyntaxError：无效语法”

问题描述

在我的应用程序中，当用户填写输入时，我应该向他/她发送电子邮件并创建该用户的实例。但由于以下错误，我无法运行我的应用程序：

Exception in thread django-main-thread:
Traceback (most recent call last):
  ...
  File "/Users/progbash/Desktop/pragmatech/pragmatechproject/pragmatechproject/urls.py", line 21, in <module>
    path('', include('pragmatechapp.urls')),
  File "/Users/progbash/Desktop/pragmatech/denvx/lib/python3.7/site-packages/django/urls/conf.py", line 34, in include
    urlconf_module = import_module(urlconf_module)
  File "/Users/progbash/Desktop/pragmatech/denvx/lib/python3.7/importlib/__init__.py", line 127, in import_module
    return _bootstrap._gcd_import(name[level:], package, level)
  File "<frozen importlib._bootstrap>", line 1006, in _gcd_import
  File "<frozen importlib._bootstrap>", line 983, in _find_and_load
  File "<frozen importlib._bootstrap>", line 967, in _find_and_load_unlocked
  File "<frozen importlib._bootstrap>", line 677, in _load_unlocked
  File "<frozen importlib._bootstrap_external>", line 728, in exec_module
  File "<frozen importlib._bootstrap>", line 219, in _call_with_frames_removed
  File "/Users/progbash/Desktop/pragmatech/pragmatechproject/pragmatechapp/urls.py", line 2, in <module>
    from . import views
  File "/Users/progbash/Desktop/pragmatech/pragmatechproject/pragmatechapp/views.py", line 26
    return render(request, 'pragmatechapp/index.html', context)
         ^
SyntaxError: invalid syntax

这是我的views.py：

def index(request): 
    context = {
        'applicants': Applicant.objects.all()
    }
    if request.method == "POST":
        applicant_name = request.POST.get('name')
        applicant_email = request.POST.get('email')
        applicant_phone = request.POST.get('phone')
        subject = 'Thank you.'
        message = 'Hi, ' + str(applicant_name)
        from_email = settings.SERVER_EMAIL
        recipient_list = [applicant_email]
        send_mail(subject, message, from_email, recipient_list)
        if request.POST.get('email'):
            Applicant.objects.create(
                name = request.POST.get('name'),
                email = request.POST.get('email'),
                phone = request.POST.get('phone')

    return render(request, 'app/index.html', context)

还有我的urls.py文件：

from django.urls import path
from . import views

urlpatterns = [
    path('', views.index, name='index')
]

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标签： pythondjangopython-3.x

解决方案

只需从索引视图更改您的以下部分...

你在那边缺少完整的括号......

if request.POST.get('email'):
        Applicant.objects.create(
            name = request.POST.get('name'),
            email = request.POST.get('email'),
            phone = request.POST.get('phone')
        )

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