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c# - 在 C# 中使用文件路径可视化文件字典的最佳实践

问题描述

我在 C# 中有一个包含 2 个字符串的字典，它代表文件名和文件的路径。我想将这些可视化为一个表单，其中包含文件夹的 TreeView 和实际文件夹的关联文件的 ListView。所以这应该显示字典中的数据，就像文件浏览器一样：

Dictionary<string, string> dict = new Dictionary<string, string>();
dict.Add("File1","Folder1\\Folder2");
dict.Add("File2","Folder1\\Folder2\\Folder3");
dict.Add("File3","Folder1");
dict.Add("File4","Folder1\\Folder2");

……

我正在寻找一个好的实现来将其呈现给一个表单：

public MethodBrowserForm(Dictionary<string, string> filesAndFolders)
    {
        InitializeComponent();


        string lastMethodFolder = "";

        Dictionary<int, List<string>> folderDictionary = new Dictionary<int, List<string>>();


        foreach (var method in filesAndFolders)
        {

            // Compare Key Values for Folders

            if (!lastMethodFolder.Equals(method.Value))
            {

                // Extract Folder
                string[] directories = filesAndFolders.Value.Split(Path.DirectorySeparatorChar);

                if (directories.Length > 1 )
                    // First Level Folders


                {
                   // Implementation for Visualization
                }


            }



            lastMethodFolder = filesAndFolders.Value;


        }   

    }

标签： c#dictionarylistviewtreeview

解决方案

尝试以下：

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace WindowsFormsApplication62
{
    public partial class Form1 : Form
    {


        public Form1()
        {
            InitializeComponent();

            Dictionary<string, string> dict = new Dictionary<string, string>();
            dict.Add("File1", "Folder1\\Folder2");
            dict.Add("File2", "Folder1\\Folder2\\Folder3");
            dict.Add("File3", "Folder1");
            dict.Add("File4", "Folder1\\Folder2");

            List<KeyValuePair<string, List<string>>> files = dict.Select(x => new KeyValuePair<string, List<string>>(x.Key, x.Value.Split(new char[] {'\\'}).ToList())).ToList();
            TreeNode root = new TreeNode();

            CreateTree(null, files);
            treeView1.ExpandAll();


        }

        public void CreateTree(TreeNode node, List<KeyValuePair<string, List<string>>> files)
        {
            var folders = files.GroupBy(x => x.Value.First()).ToList();
            foreach (var folder in folders)
            {
                TreeNode newNode = new TreeNode(folder.Key);
                if (node == null)
                {
                    treeView1.Nodes.Add(newNode);
                }
                else
                {
                    node.Nodes.Add(newNode);
                }
                List<KeyValuePair<string, List<string>>> child = new List<KeyValuePair<string, List<string>>>();
                foreach (KeyValuePair<string, List<string>> file in folder)
                {
                    if (file.Value.Count == 1)
                    {
                        newNode.Nodes.Add(file.Key);
                    }
                    else
                    {
                        KeyValuePair<string, List<string>> newFile = new KeyValuePair<string, List<string>>(file.Key, file.Value.Skip(1).ToList());
                        child.Add(newFile);
                    }
                }
                if (child != null)
                {
                    CreateTree(newNode, child);
                }
            }
        }




    }
}

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