首页 > 解决方案 > 如何让 wc 接受管道文件而不是标准输入来获取输入?

问题描述

这是一个家庭作业问题。任务是复制命令:ls | wc -l在 C 程序中使用execlpfork和管道。

我的方法

我认为这个问题可以这样解决:

  1. 创建管道文件:pipe.txt
  2. 使用创建子进程fork()
    • stdout将子进程映射到pipe.txt
    • 执行ls使用execlp
    • 这将输出ls放入pipe.txt
  3. 父进程内部
    • stdin将父进程映射到pipe.txt
    • 执行wc -lusingexeclp而不提供任何进一步的参数,因此它从 stdin 读取
    • 由于stdout这个父进程的仍然是终端本身,所以它应该打印出终端上的行数

我的代码

#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <sys/types.h>
#include <unistd.h> 
#include <fcntl.h> 
#include <errno.h> 
#include <sys/wait.h>

int main() {
        int pipefds[2];
        int returnstatus;
        int pid;

        char argArr[30] = {'\n'};

        returnstatus = pipe(pipefds);
        if (returnstatus == -1) {
                printf("Unable to create pipe\n");
                return 1;
        }

        int file_desc = open("pipe.txt", O_RDWR | O_APPEND | O_CREAT); 

        pid = fork();

        if (pid == 0) {
                int copy_desc = dup2(file_desc, 1);
                execlp("ls", "ls", NULL);
        } else {
                int copy_desc = dup2(file_desc, 0);
                close(copy_desc);
                execlp("wc", "wc", "-l", NULL);
        }
        return 0;
}

实际输出

main.cpp blabla.cpp main pipe.txt
>

问题

这有两个问题:

  1. 既然我把孩子的stdout设置为pipe.txt文件,为什么还在终端上输出呢?注意:它也将输出放入pipe.txt文件中。但是为什么它也显示在终端上?

  2. 它开始等待用户提供输入?它不应该从管道文件而不是用户获取输入吗?

预期产出

5

*如果当前目录有5个文件

尝试过的解决方案

  1. 仅使用管道:(出现错误的文件描述符错误)
int main() {
        int pipefds[2];
        int returnstatus;
        int pid;

        returnstatus = pipe(pipefds);
        if (returnstatus == -1) {
                printf("Unable to create pipe\n");
                return 1;
        }

        pid = fork();

        if (pid == 0) {
                dup2(pipefds[0], 1);
                close(pipefds[1]);
                execlp("ls", "ls", NULL);
        } else {
                dup2(pipefds[1], 0);
                close(pipefds[0]);
                execlp("wc", "wc", "-l", NULL);
        }
        return 0;
}

标签: clinuxpipeexec

解决方案


感谢您的有用评论。

代码中的问题是我根本没有使用管道。我正在使用我创建的文件完成所有工作。所以这是基本问题。

这是新代码:

#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <sys/types.h>
#include <unistd.h> 
#include <fcntl.h> 
#include <errno.h> 
#include <sys/wait.h>

int main() {
    // Step1. Create pipe file descriptors: pipefd[0] for reading from pipe, pipefd[1] for writing to the pipe
    int pipefds[2];

    // Helping variables
    int returnstatus;
    int pid;

    // Step2. Create a pipe with the file descriptors
    returnstatus = pipe(pipefds);

    // Check if pipe was successfully created
    if (returnstatus == -1) {
        printf("Unable to create pipe\n");
        return 1;
    }

    // Step3. Fork to create a child process
    pid = fork();

    if (pid == 0) {
        // Inside the child process

        // Step4. Duplicate the file descriptor of the write end of the pipe and set it equal to the stdout of the process 
        dup2(pipefds[1], 1);

        // Step5. Close both ends of the pipe
        close(pipefds[0]);
        close(pipefds[1]);

        // Step6. Execute the LS command. It ouputs to stdout which we set equal to the pipe in Step4.
        // So essentially, we send all output of ls to our pipe 
        returnstatus = execlp("ls", "ls", NULL);

        // Error checking the execlp command
        if (returnstatus == -1){
            perror("Error executing execlp: ");
        }
    } else {
        // Inside the parent process

        // Step7. Duplicate the file descriptor the READ end of the pipe and set it equal to the stdin of the process
        dup2(pipefds[0], 0);

        // Step8. Close the both ends of the pipe
        close(pipefds[0]);
        close(pipefds[1]);

        // Step9. Execute the WC command. It takes the file as an argument usually but if no file is given, it will take
        // stdin as input. Since the stdin is the pipe, therefore it will read all the data from the pipe.
        // The output of the wc command is stdout which is the terminal for this process so we will get the number of
        // files/directories in the current directory as an output on the terminal
        returnstatus = execlp("wc", "wc", "-l", NULL);

        // Error checking the execlp command
        if (returnstatus == -1){
            perror("Error executing execlp: ");
        }
    }
    return 0;
}


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