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html - D3.Js 中的动画路径多系列折线图

问题描述

我想重现一个动画多系列折线图。

代码如下，

<!DOCTYPE html>
<meta charset="utf-8">
<style>

body {
  font: 12px Helvetica;
}

.axis line {
  fill: none;
  stroke: #000;
  shape-rendering: crispEdges;
}

.x.axis path {
  display: none;
}

.line {
  fill: none;
  stroke: steelblue;
  stroke-width: 2px;
}

</style>
<body>
<script src="https://d3js.org/d3.v3.js"></script>
<script>

var margin = {top: 20, right: 50, bottom: 30, left: 50},
    width = 630 - margin.left - margin.right,
    height = 400 - margin.top - margin.bottom;

var parseDate = d3.time.format("%Y-%m-%d").parse;

var x = d3.time.scale()
    .range([0, width]);

var y = d3.scale.linear()
    .range([height, 0]);

var color = d3.scale.category10();

var xAxis = d3.svg.axis()
    .scale(x)
    .ticks(5)
    .innerTickSize(15)
    .outerTickSize(0)
    .orient("bottom");

var yAxis = d3.svg.axis()
    .scale(y)
    .tickFormat(function(d) { return d + "%";})
    .ticks(5)
    .innerTickSize(15)
    .outerTickSize(0)
    .orient("left");

var line = d3.svg.line()
    .interpolate("basis")
    .x(function(d) { return x(d.date); })
    .y(function(d) { return y(d.price); });


var svg = d3.select("body").append("svg")
    .attr("width", width + margin.left + margin.right)
    .attr("height", height + margin.top + margin.bottom)
  .append("g")
    .attr("transform", "translate(" + margin.left + "," + margin.top + ")");

d3.csv('http://localhost:8000/Desktop/Dat/data.csv', function(error, data) {
  color.domain(d3.keys(data[0]).filter(function(key) { return key !== "date"; }));

  data.forEach(function(d) {
    d.date = parseDate(d.date);
  });

  var companies = color.domain().map(function(name) {
    return {
      name: name,
      values: data.map(function(d) {
        return {date: d.date, price: +d[name]};
      })
    };
  });


  x.domain(d3.extent(data, function(d) { return d.date; }));

  y.domain([
    d3.min(companies, function(c) { return d3.min(c.values, function(v) { return v.price; }); }),
    d3.max(companies, function(c) { return d3.max(c.values, function(v) { return v.price; }); })
  ]);

  svg.append("g")
      .attr("class", "x axis")
      .attr("transform", "translate(0," + height + ")")
      .call(xAxis);

  svg.append("g")
      .attr("class", "y axis")
      .call(yAxis);


  svg.append("line")
        .attr(
        {
            "class":"horizontalGrid",
            "x1" : 0,
            "x2" : width,
            "y1" : y(0),
            "y2" : y(0),
            "fill" : "none",
            "shape-rendering" : "crispEdges",
            "stroke" : "black",
            "stroke-width" : "1px",
            "stroke-dasharray": ("3, 3")
        });


  var company = svg.selectAll(".company")
      .data(companies)
    .enter().append("g")
      .attr("class", "company");



  var path = svg.selectAll(".company").append("path")
      .attr("class", "line")
      .attr("d", function(d) { return line(d.values); })
      .style("stroke", function(d) { if (d.name == "Airbus") 
                                        {return "rgb(000,255,000)"}
                                      else {return "#000";}
                                         });



  //var totalLength = path.node().getTotalLength();
/*
console.log(path);
console.log(path.node());
console.log(path[0][0]);
console.log(path[0][1]);
*/
var totalLength = [path[0][0].getTotalLength(), path[0][1].getTotalLength()];

console.log(totalLength);


   d3.select(path[0][0])
      .attr("stroke-dasharray", totalLength[0] + " " + totalLength[0] ) 
      .attr("stroke-dashoffset", totalLength[0])
      .transition()
        .duration(15000)
        .ease("linear")
        .attr("stroke-dashoffset", 0);

   d3.select(path[0][1])
      .attr("stroke-dasharray", totalLength[1] + " " + totalLength[1] )
      .attr("stroke-dashoffset", totalLength[1])
      .transition()
        .duration(15000)
        .ease("linear")
        .attr("stroke-dashoffset", 0);

});

</script>

在此处使用此数据可以正常工作https://www.kaggle.com/dataset/465051e62819ab5a9903eb1658c33492adc374f4075504f10c24307505cb4e55

注意：这是此处示例的复制品http://bl.ocks.org/atmccann/8966400

我想使用此数据重现相同的图表

我得到这个：

Error: <path> attribute d: Expected number, "MNaN,344.43863848…".

我试图格式化我的第二个数据，使其与第一个数据完全相似，即通过将第一个数据重命名为“Airbus”和“Boeing”列，但仍然不断出现错误。

标签： htmlanimationd3.jslinechart

解决方案

添加了带有虚拟数据集的代码。数据集的形状与您指定的形状相似。您只需要按照您给出的示例中显示的方式使用它。

你需要做的两个改变：

  1. 更改日期的解析。替换为以下行：

    var parseDate = d3.time.format("%d/%m/%Y").parse

  2. 由于我们有更多的国家数据，因此使用不同的逻辑进行着色。

    var path = svg.selectAll(".company").append("path") .attr("class", "line") .attr("d", function(d) { return line(d.values); }) .style("stroke", function(d) { return color(d.name) });

<!DOCTYPE html>
<meta charset="utf-8">
<style>
  body {
    font: 12px Helvetica;
  }
  
  .axis line {
    fill: none;
    stroke: #000;
    shape-rendering: crispEdges;
  }
  
  .x.axis path {
    display: none;
  }
  
  .line {
    fill: none;
    stroke: steelblue;
    stroke-width: 2px;
  }
</style>

<body>
  <script src="https://d3js.org/d3.v3.js"></script>
  <script>
    var margin = {
        top: 20,
        right: 50,
        bottom: 30,
        left: 50
      },
      width = 630 - margin.left - margin.right,
      height = 400 - margin.top - margin.bottom;
    debugger;
    var parseDate = d3.time.format("%d/%m/%Y").parse;

    var x = d3.time.scale()
      .range([0, width]);

    var y = d3.scale.linear()
      .range([height, 0]);

    var color = d3.scale.category10();

    var xAxis = d3.svg.axis()
      .scale(x)
      .ticks(5)
      .innerTickSize(15)
      .outerTickSize(0)
      .orient("bottom");

    var yAxis = d3.svg.axis()
      .scale(y)
      .tickFormat(function(d) {
        return d + "%";
      })
      .ticks(5)
      .innerTickSize(15)
      .outerTickSize(0)
      .orient("left");

    var line = d3.svg.line()
      .interpolate("basis")
      .x(function(d) {
        return x(d.date);
      })
      .y(function(d) {
        return y(d.price);
      });


    var svg = d3.select("body").append("svg")
      .attr("width", width + margin.left + margin.right)
      .attr("height", height + margin.top + margin.bottom)
      .append("g")
      .attr("transform", "translate(" + margin.left + "," + margin.top + ")");

    data = [{
        date: '1/31/1995',
        Austria: '23',
        Belgium: '14',
        Bulgaria: '-96',
      },
      {
        date: '1/31/1996',
        Austria: '-23',
        Belgium: '114',
        Bulgaria: '50',
      },
      {
        date: '1/31/1997',
        Austria: '27',
        Belgium: '-14',
        Bulgaria: '96',
      },
    ]

    color.domain(d3.keys(data[0]).filter(function(key) {
      return key !== "date";
    }));

    data.forEach(function(d) {
      d.date = parseDate(d.date);
    });

    var companies = color.domain().map(function(name) {
      return {
        name: name,
        values: data.map(function(d) {
          return {
            date: d.date,
            price: +d[name]
          };
        })
      };
    });


    x.domain(d3.extent(data, function(d) {
      return d.date;
    }));

    y.domain([
      d3.min(companies, function(c) {
        return d3.min(c.values, function(v) {
          return v.price;
        });
      }),
      d3.max(companies, function(c) {
        return d3.max(c.values, function(v) {
          return v.price;
        });
      })
    ]);

    svg.append("g")
      .attr("class", "x axis")
      .attr("transform", "translate(0," + height + ")")
      .call(xAxis);

    svg.append("g")
      .attr("class", "y axis")
      .call(yAxis);


    svg.append("line")
      .attr({
        "class": "horizontalGrid",
        "x1": 0,
        "x2": width,
        "y1": y(0),
        "y2": y(0),
        "fill": "none",
        "shape-rendering": "crispEdges",
        "stroke": "black",
        "stroke-width": "1px",
        "stroke-dasharray": ("3, 3")
      });


    var company = svg.selectAll(".company")
      .data(companies)
      .enter().append("g")
      .attr("class", "company");



    var path = svg.selectAll(".company").append("path")
      .attr("class", "line")
      .attr("d", function(d) {
        return line(d.values);
      })
      .style("stroke", function(d) {
        return color(d.name)
      });



    var totalLength = path.node().getTotalLength();

    d3.select(path[0][0])
      .attr("stroke-dasharray", totalLength[0] + " " + totalLength[0])
      .attr("stroke-dashoffset", totalLength[0])
      .transition()
      .duration(5000)
      .ease("linear")
      .attr("stroke-dashoffset", 0);

    d3.select(path[0][1])
      .attr("stroke-dasharray", totalLength[1] + " " + totalLength[1])
      .attr("stroke-dashoffset", totalLength[1])
      .transition()
      .duration(5000)
      .ease("linear")
      .attr("stroke-dashoffset", 0);
  </script>

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