首页 > 解决方案 > 枚举列表中具有相似字符串的函数

问题描述

编写脚本来读取多个 csv 文件。我有一个包含 3 个不同条形码的列表。每个代码都有三个不同的文件。每个代码都有相同的前缀“5SvF9yM6ldXGRpBz”。这是较长的条形码列表的一部分。

我有另一个找到条形码的目录列表。为了让脚本运行,我需要所有三个文件

我的目标是建立一个包含不同条形码和目录的字典。我的输出有问题。三个条码之一丢失。'5SvF9yM6ldXGRpBz1'。我认为问题在于 for 循环中的枚举函数。

 directories = ['C:/Desktop/5SvF9yM6ldXGRpBz1_FIRST.csv',
'C:/Desktop/5SvF9yM6ldXGRpBz11_FIRST.csv',
'C:/Desktop/5SvF9yM6ldXGRpBz12_FIRST.csv',
'C:/Desktop/5SvF9yM6ldXGRpBz1_SECOND.csv',
'C:/Desktop/5SvF9yM6ldXGRpBz11_SECOND.csv',
'C:/Desktop/5SvF9yM6ldXGRpBz12_SECOND.csv',
'C:/Desktop/5SvF9yM6ldXGRpBz1_THIRD.csv',
'C:/Desktop/5SvF9yM6ldXGRpBz11_THIRD.csv',
'C:/Desktop/5SvF9yM6ldXGRpBz12_THIRD.csv']

barcodes = ['5SvF9yM6ldXGRpBz1',
'5SvF9yM6ldXGRpBz11',
'5SvF9yM6ldXGRpBz12',
'5SvF9yM6ldXGRpBz1',
'5SvF9yM6ldXGRpBz11',
'5SvF9yM6ldXGRpBz12',
'5SvF9yM6ldXGRpBz1',
'5SvF9yM6ldXGRpBz11',
'5SvF9yM6ldXGRpBz12']

#print(directories)
#print(barcodes)

barcodes = list(set(barcodes))
barcodes = [s for s in barcodes if "5SvF9yM6ldXGRpBz" in s] #Want to process codes with this prefix 
directories = list(set(directories))
#print(directories)
directories = [s for s in directories if "5SvF9yM6ldXGRpBz" in s]
#print(directories)

barcode_dirs_indexes =[]
for b_code in barcodes:
   #print(b_code)
   index = [i for i,x in enumerate(directories) if b_code in x] #I think the issue is here
   barcode_dirs_indexes.append(index)
   #print(barcode_dirs_indexes)

barcode_dirs = [[directories[x] for x in y] for y in barcode_dirs_indexes]

# only process barcode with 3 directories, i.e. the barcode has 3 files 
data_barcode_dir_indx = [i for i,x  in enumerate(barcode_dirs) if len(x) == 3 ]
data_barcode_dirs = [x for x in barcode_dirs if len(x) == 3]
#print(data_barcode_dir_indx)
#print(data_barcode_dirs)
complete_data_barcodes = [barcodes[x] for x in data_barcode_dir_indx]
print(complete_data_barcodes)
dir_file_dict = dict(zip(complete_data_barcodes, data_barcode_dirs)) 

dir_file_dict 的输出:缺少条形码:5SvF9yM6ldXGRpBz1

{'5SvF9yM6ldXGRpBz12': ['C:/Desktop/5SvF9yM6ldXGRpBz12_FIRST.csv', 
'C:/Desktop/5SvF9yM6ldXGRpBz12_THIRD.csv', 'C:/Desktop/5SvF9yM6ldXGRpBz12_SECOND.csv'], 
'5SvF9yM6ldXGRpBz11': ['C:/Desktop/5SvF9yM6ldXGRpBz11_FIRST.csv', 
'C:/Desktop/5SvF9yM6ldXGRpBz11_SECOND.csv', 'C:/Desktop/5SvF9yM6ldXGRpBz11_THIRD.csv']}

标签: pythonpython-3.xloopsdictionaryenumerate

解决方案


你可以这样做:

d = {}
for i,j in zip(barcodes, directories):
  if not d.get(i):
    d[i] = []
  d[i].append(j)

print(d)

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