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首页 > 解决方案 > 文件保存错误 [错误] 无法传递非平凡可复制类型的对象 'std::string {aka class std::basic_string}' 通过 '...'

c++ - 文件保存错误 [错误] 无法传递非平凡可复制类型的对象 'std::string {aka class std::basic_string}' 通过 '...'

问题描述

我在编码世界中很新，所以我似乎无法理解这个错误。fprintf我正在创建一个产品管理程序，您可以在其中输入产品详细信息并将该数据放在文件中，然后通过 cmd 从文件中查看它，但是每当我使用或时，此错误都会不断弹出fputs。

我的代码：

#include<iostream>
#include<stdio.h>
#include<string.h>
using namespace std;

struct product{
    string Id,Name,Brand;
    int type, price, quan;
    product *next;
};
int main(){
    product *a,*b,*c,*d,*e,*f;
    a = new product;
    b = new product;
    c = new product;
    d = new product;
    e = new product;
    f = new product;
    FILE *productRecord;
    productRecord = fopen("Product Record","r");
    int choice;
    cout << "\nProduct Record\n1)Add Product\n2)Update Product Details\n3)Delete Product\n4)View Product By Brand or Type\n5)Exit\n\nEnter Choice: ";
    cin >> choice;
        if(choice == 1){
            char tempId[11],tempName[60],tempBrand[60];
            int temp_type, temp_price, temp_quan;
            productRecord = fopen("Product Record","a");
            cout << "Enter Product ID No.(Maximum of 10 Digits): ";
            cin >> tempId;
            a -> Id = tempId;
            a -> next = b;
            cout << "Enter Product Name(No Special Character): ";
            cin >> tempName;
            b -> Name = tempName;
            b -> next = c;
            cout << "Types:Canned(1),Frozen(2),Drinks(3),Produce(4),Meat/Seafood(5),Cleaning(6)\nEnter Product Type(1-6): ";
            cin >> temp_type;
            c -> type = temp_type;
            c -> next = d;
            cout << "Enter Product Brand(No spaces): ";
            cin >> tempBrand;
            d -> Brand = tempBrand;
            d -> next = e;
            cout << "Enter Product Price: ";
            cin >> temp_price;
            e -> price = temp_price;
            e -> next = f;
            cout << "Enter Product Quantity: ";     
            cin >> temp_quan;
            f -> quan = temp_quan;
            f -> next = NULL;

            fprintf(productRecord, "%s", a -> Id); //this is the error





            fclose(productRecord);
        }
        else if(choice == 2){
        }
        else if(choice == 3){
        }
        else if(choice == 4){
        }
        else if(choice == 5){
        }
    return 0;
}

标签： c++

解决方案

错误信息非常清楚。您不能使用stringwith fprintf。

fprintf(productRecord, "%s", a -> Id);

需要改为

fprintf(productRecord, "%s", a->Id.c_str());

或者，更好的是，不要混合使用 C 和 C++，而是使用ofstream

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