javascript - 如何从对象数组中删除一个值？

Question

我有一个返回对象数组的函数，我希望数据数组返回像这样的“数据”：[5466, 25]，pointsExchanged 和 pointsExpired 返回一个像这样的对象数组：[ { sum: '5466' } ]

export const getPieChart = async () => {
  const [pointsExchanged, pointsExpired] = await Promise.all([
    conn("statements")
      .sum("value")
      .where('type', 'deposito'),
    conn("statements")
      .sum("value")
      .where('type', 'exchange'),
  ]);

  return {
    labels: ['Pontos trocados', 'Pontos expirados', 'Pontos atribuidos'],
    datasets: [
      {
        backgroundColor: ["blue", 'red'],
        data: [pointsExchanged, pointsExpired]
      },
    ]
  };
}

函数响应：

{
    "labels": [
        "Pontos trocados",
        "Pontos expirados",
        "Pontos atribuidos"
    ],
    "datasets": [
        {
            "backgroundColor": [
                "blue",
                "red"
            ],
            "data": [
                [
                    {
                        "sum": "5466"
                    }
                ],
                [
                    {
                        "sum": "25"
                    }
                ]
            ]
        }
    ] }

我希望如何回应：

{
        "labels": [
            "Pontos trocados",
            "Pontos expirados",
            "Pontos atribuidos"
        ],
        "datasets": [
            {
                "backgroundColor": [
                    "blue",
                    "red"
                ],
                "data": [5466, 25],

            }
        ] }

标签： javascriptnode.js

Answer 1

只需映射它们并提取sum属性，然后使用扩展运算符将它们合并...

data: [
  ...pointsExchanged.map(point => Number(point.sum)), 
  ...pointsExpired.map(point => Number(point.sum))
]

const pointsExchanged = [{"sum": "5466"}];
const pointsExpired = [{"sum": "25"}];

const data = [
  ...pointsExchanged.map(point => Number(point.sum)), 
  ...pointsExpired.map(point => Number(point.sum))
];

console.log(data)