首页 > 解决方案 > flink计数不同的问题

问题描述

现在我们使用翻滚窗口来计算不同的。我们遇到的问题是,如果我们将翻滚窗口从一天延长到一个月,我们就无法获得现在不同的数字。这意味着如果我们将滚动窗口设置为 1 个月,我们得到的数字是每个月的第一天。我现在如何获得当前的不同计数(现在是 3 月 9 日)?

package flink.trigger;

import org.apache.flink.api.common.state.ReducingState;
import org.apache.flink.api.common.state.ReducingStateDescriptor;
import org.apache.flink.api.common.typeutils.base.LongSerializer;
import org.apache.flink.streaming.api.windowing.triggers.Trigger;
import org.apache.flink.streaming.api.windowing.triggers.TriggerResult;
import org.apache.flink.streaming.api.windowing.windows.TimeWindow;

import java.text.SimpleDateFormat;
import java.util.Date;

public class CustomCountDistinctTigger extends Trigger<Object, TimeWindow> {

    private final ReducingStateDescriptor<Long> timeState =
            new ReducingStateDescriptor<>("fire-interval", new DistinctCountAggregateFunction(), LongSerializer.INSTANCE);
    private long interval;


    public CustomCountDistinctTigger(long interval) {
        this.interval = interval;
    }

    @Override
    public TriggerResult onElement(Object element, long timestamp, TimeWindow window, TriggerContext ctx) throws Exception {
        ReducingState<Long> fireTimestamp = ctx.getPartitionedState(timeState);

        timestamp = ctx.getCurrentProcessingTime();

        if (fireTimestamp.get() == null) {
            long start = timestamp - (timestamp % interval);
            long nextFireTimestamp = start + interval;
            ctx.registerProcessingTimeTimer(nextFireTimestamp);
            fireTimestamp.add(nextFireTimestamp);
            return TriggerResult.CONTINUE;
        }
        return TriggerResult.CONTINUE;
    }

    @Override
    public TriggerResult onProcessingTime(long time, TimeWindow window, TriggerContext ctx) throws Exception {
//        System.out.println("onProcessingTime called at "+System.currentTimeMillis() );
//        return TriggerResult.FIRE_AND_PURGE;
        SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
        System.out.println(df.format(new Date()));
        //interval
        ReducingState<Long> fireTimestamp = ctx.getPartitionedState(timeState);

        if(window.maxTimestamp() == time) {
            return TriggerResult.FIRE_AND_PURGE;
        }
        else if (fireTimestamp.get().equals(time)) {
            fireTimestamp.clear();
            fireTimestamp.add(time + interval);
            ctx.registerProcessingTimeTimer(time + interval);
            return TriggerResult.FIRE;
        }
        return TriggerResult.CONTINUE;
    }

    @Override
    public TriggerResult onEventTime(long time, TimeWindow window, TriggerContext ctx) throws Exception {
        return TriggerResult.CONTINUE;
    }

    @Override
    public void clear(TimeWindow window, TriggerContext ctx) throws Exception {

    }

}


distinct count:
DataStreamSink<Tuple2<String, Integer>> finalResultStream = keyedStream
                            .flatMap(new KPIDistinctDataFlatMapFunction(inputSchema))
                            .map(new SwapMap())
                            .keyBy(new WordKeySelector())
                            .window(TumblingProcessingTimeWindows.of(org.apache.flink.streaming.api.windowing.time.Time.minutes(5)))
                            .trigger(new CustomCountDistinctTigger(1 * 60 * 6000))
                            .aggregate(new DistinctCountAggregateFunction())
                            .print("final print");

标签: apache-flinkflink-cepflink-sql

解决方案


您可以定义一个自定义触发器,每天返回一次 FIRE 以触发中间结果,然后在月底执行 FIRE_AND_PURGE 以关闭窗口。

每次 Trigger 返回 FIRE 时,都会通过调用 your 的process()方法来评估您的窗口ProcessWindowFunction,此时它可以使用Collector提供的 生成结果。FIRE_AND_PURGE 最后一次评估窗口,然后销毁它。

另请参阅此问题的答案——如何在窗口化流 ETL 中显示中间结果?- 涵盖了一个相关主题。


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