haskell - Hoopl:图构建和不可达块的自动删除
问题描述
我正在使用 Hoopl 库开展一个项目,但我遇到了一个障碍,这表明我并不完全了解引擎盖下发生了什么。简而言之,Hoopl 似乎认为我的图表中的某些块无法到达(IMO)它不应该。我正在实现一个稀疏的条件常数传播,所以我确实希望某些块变得无法访问,但不是所有块!下面是一个示例,取自我用来制作原型的 HUnit 测试套件。该示例使用了几个未在此处定义的函数,但我为那些确认它们独立工作的单独的单元测试,特别是fromHoopl . toHoopl x
按预期工作的函数,等等。
我期望发生的是这block_cprop_out
应该是运行这个 pass 的结果,但实际结果只是 const 折叠版本block_cprop_in_0
:true 和 false 分支都被消除了。HUnit 测试的输出位于代码片段下方。
为了概括我在高层次上所做的事情,我为每个块创建了一个封闭/封闭的 Hoopl 图,然后将这些图与Hoopl.|*><*|
. 我使用一个简单Data.Map
的方法来跟踪 Hoopl 为用户标签分配的唯一标签,这样,当我重写 a 时Branch userlabel
,我可以将 Hoopl 后继标签修改为正确的 Hoopl Label
。然而,Hoopl 似乎认为真假分支块在这里都不可达,因为在我运行这个前向分析和重写之后,我得到一个只包含入口块的图。
block_cprop_out
这里有点奇怪,因为我的fromHoopl
函数只是调用Hoopl.foldGraphNodes
将整个 HooplGraph a
变成一个简单[a]
的检查。
一个单独的测试证实,使用相同的图形构造方法(连接封闭/封闭块)来往返这个块列表可以按预期工作;似乎消除无法访问的块是由Hoopl.analyzeAndRewrite{Fwd,Bwd}
.
像我在这里做的那样拼接一个封闭/封闭块的列表是否正确?如果是这样,任何人都可以在这里看到任何可能导致 Hoopl 认为区块无法访问的可疑内容吗?
block_cprop_in_0 = [ --test for constprop
L $ Label "entry",
O $ Sub (Reg "r0") (Reg "r0"),
T $ CondBranch (Reg "r0") (Label "tb") (Label "fb")
]
block_cprop_in_1 = [ -- test for constprop
L $ Label "tb",
O $ Sub (Reg "r1") (Reg "r0"),
T $ Halt
] -- this block is unreachable from the CondBranch in block_cprop_in_0
block_cprop_in_2 = [ -- test for constprop
L $ Label "fb",
O $ Sub (Reg "r2") (Reg "r0"), --should get rewritten as a SubI
T $ Halt
]
block_cprop_out = [ --test for constprop
L $ Label "entry",
O $ Sub (Reg "r0") (Reg "r0"),
T $ Branch (Label "fb"),
L $ Label "fb",
O $ SubI 0 (Reg "r2"),
T $ Halt
]
test_hoopl_6 =
let p = [block_cprop_in_0, block_cprop_in_1, block_cprop_in_2]
p' :: (H.Graph (Node Instruction) H.C H.C) = H.runSimpleUniqueMonad $ H.runWithFuel H.infiniteFuel $ (transform p :: H.SimpleFuelMonad (H.Graph (Node Instruction) H.C H.C))
unP' :: [Instruction] = fromHoopl p'
in unP' @?= block_cprop_out
where
transform :: (H.CheckpointMonad m, H.FuelMonad m, H.UniqueMonad m) => [[Instruction]] -> m (H.Graph (Node Instruction) H.C H.C)
transform prog = do
(hlms, ps) <- liftM unzip $ forM prog toHoopl
let hlm = Map.unions hlms
let p = foldl (H.|*><*|) H.emptyClosedGraph ps
let hooplLabelFor = fromJust . flip Map.lookup hlm
let eLabel = hooplLabelFor $ Label "entry"
let registers = ["r0", "r1", "r2", "r3"]
p' <- runConstProp registers hooplLabelFor eLabel p
return p'
constLattice :: H.DataflowLattice ConstFact
constLattice = H.DataflowLattice
{ H.fact_name = "Register Contents"
, H.fact_bot = Map.empty
, H.fact_join = H.joinMaps (H.extendJoinDomain constFactAdd)
}
where
constFactAdd _ (H.OldFact old) (H.NewFact new)
= if new == old then (H.NoChange, H.PElem new)
else (H.SomeChange, H.Top)
-- initially all registers have unknown contents
initFact :: [Register] -> ConstFact
initFact regs = Map.fromList $ [(r, H.Top) | r <- regs]
-- transfer function: register value is a constant
regIsConstant :: (Label -> H.Label) -> H.FwdTransfer (Node Instruction) ConstFact
regIsConstant hooplLabelFor = H.mkFTransfer rc
where
rc :: Node Instruction e x -> ConstFact -> H.Fact x ConstFact
rc (NodeInit _ _) f = f
-- subtracting a register from itself yields zero
rc (NodeCont (O (Sub (Reg a) (Reg b)))) f
= if a == b then Map.insert a (H.PElem 0) f else f
rc (NodeCont (O (Sub _ (Reg x)))) f = Map.insert x H.Top f
rc (NodeCont (O (SubI _ (Reg x)))) f = Map.insert x H.Top f
rc (NodeCont (O (SubM _ (Reg x)))) f = Map.insert x H.Top f
rc (NodeCont (O (Load _ (Reg x)))) f = Map.insert x H.Top f
rc (NodeCont (O (Store _ (Reg x)))) f = Map.insert x H.Top f
rc (NodeCont (O (CmpEq _ (Reg x)))) f = Map.insert x H.Top f
rc (NodeCont (O (CmpLt _ (Reg x)))) f = Map.insert x H.Top f
rc (NodeCont (O _)) f = f
rc (NodeTerm (T Halt) _) f = H.mkFactBase constLattice []
rc (NodeTerm (T (Branch l)) _) f = H.mapSingleton (hooplLabelFor l) f
-- if we take the false branch of a CondBranch then the condition register contains zero
rc (NodeTerm (T (CondBranch (Reg x) tl fl)) _) f
= H.mkFactBase constLattice
[(hooplLabelFor tl, f),
(hooplLabelFor fl, Map.insert x (H.PElem 0) f)]
-- rewrite function: replace use of reg with constant contents
constProp :: forall m. H.FuelMonad m => (Label -> H.Label) -> H.FwdRewrite m (Node Instruction) ConstFact
constProp hooplLabelFor = H.mkFRewrite cp
where
cp :: Node Instruction e x -> ConstFact -> m (Maybe (H.Graph (Node Instruction) e x))
cp node f
= return $ rw hooplLabelFor (lookup f) node
rw :: (Label -> H.Label) -> (Register -> Maybe Integer) -> Node Instruction e x -> (Maybe (H.Graph (Node Instruction) e x))
rw hooplLabelFor valueOf inst =
case inst of
-- if we see a subtract with constant, turn it into a SubI
(NodeCont (O (Sub (Reg x) (Reg y)))) ->
case (valueOf x, valueOf y) of
(Just xi, _) -> Just $ H.mkMiddle $ NodeCont $ O $ SubI xi (Reg y)
(_, Just yi) -> Just $ H.mkMiddle $ NodeCont $ O $ SubI yi (Reg x)
_ -> Nothing
-- if we see a CondBranch on a constant, turn it into a Branch
(NodeTerm (T (CondBranch (Reg x) tl fl)) _) ->
case (valueOf x) of
(Just xi) ->
if 0 == xi then
Just $ H.mkLast $ NodeTerm (T $ Branch fl) [hooplLabelFor fl]
else
Just $ H.mkLast $ NodeTerm (T $ Branch tl) [hooplLabelFor tl]
_ -> Nothing
_ -> Nothing
lookup :: ConstFact -> Register -> Maybe Integer
lookup f x = case Map.lookup x f of
Just (H.PElem v) -> Just v
_ -> Nothing
constPropPass :: H.FuelMonad m => (Label -> H.Label) -> H.FwdPass m (Node Instruction) ConstFact
constPropPass hooplLabelFor = H.FwdPass
{ H.fp_lattice = constLattice
, H.fp_transfer = regIsConstant hooplLabelFor
, H.fp_rewrite = constProp hooplLabelFor
}
runConstProp :: (H.CheckpointMonad m, H.FuelMonad m) => [Register] -> (Label -> H.Label) -> H.Label -> (H.Graph (Node Instruction) H.C H.C) -> m (H.Graph (Node Instruction) H.C H.C)
runConstProp registers hooplLabelFor entry graph = do
(graph', _, _) <- H.analyzeAndRewriteFwd (constPropPass hooplLabelFor) (H.JustC [entry]) graph (H.mapSingleton entry $ initFact registers)
return graph'
HUnit 输出为:
hoopl_6: [Failed]
expected: [L (Label "entry"),O (Sub (Reg "r0") (Reg "r0")),T (Branch (Label "fb")),L (Label "fb"),O (SubI 0 (Reg "r2")),T Halt]
but got: [L (Label "entry"),O (Sub (Reg "r0") (Reg "r0")),T (Branch (Label "fb"))]
解决方案
事实证明,问题确实不在这段代码中。
我没有在顶层输入标签映射单子,而是在转换的叶子中放置了对 runLabelMapM 的单独调用,这意味着我不小心为程序中的每个用户标签分配了唯一的 Hoopl 标签,而不是重用 Hoopl程序重用用户标签的标签。
当然,这意味着 agoto L3
和后续代码中的匹配L3:
被映射到不同的Hoopl 标签,而不是同一个 Hoopl 标签;true 和 false 分支块是绝对无法访问的,因为在 Hoopl 看来,它们看起来好像是我写的:
block_cprop_in_0 = [ --test for constprop
L $ Label "1",
O $ Sub (Reg "r0") (Reg "r0"),
T $ CondBranch (Reg "r0") (Label "2") (Label "3")
]
block_cprop_in_1 = [ -- test for constprop
L $ Label "4",
O $ Sub (Reg "r1") (Reg "r0"),
T $ Halt
] -- this block is unreachable from the CondBranch in block_cprop_in_0
block_cprop_in_2 = [ -- test for constprop
L $ Label "5",
O $ Sub (Reg "r2") (Reg "r0"), --should get rewritten as a SubI
T $ Halt
]
最后只是一个单子线程陷阱!
对于后代,这是正确的代码:我只需要将函数runHooplLabelMapM
外部提升toHoopl
到顶层。
test_hoopl_6 =
let p = [block_cprop_in_0, block_cprop_in_1, block_cprop_in_2]
p' :: (H.Graph (Node Instruction) H.C H.C) = H.runSimpleUniqueMonad $ H.runWithFuel H.infiniteFuel $ ((transform p) :: H.SimpleFuelMonad (H.Graph (Node Instruction) H.C H.C))
unP' :: [Instruction] = fromHoopl p'
in unP' @?= block_cprop_out
where
convert prog = do
ps <- forM prog (toHoopl @[] @Instruction @Label)
let p = foldl (H.|*><*|) H.emptyClosedGraph ps
return p
transform :: (H.CheckpointMonad m, H.FuelMonad m, H.UniqueMonad m) => [[Instruction]] -> m (H.Graph (Node Instruction) H.C H.C)
transform p = do
(hlm, prog) <- runHooplLabelMapM Map.empty $ convert p
let registers = ["r0", "r1", "r2", "r3"]
let hooplLabelFor = fromJust . flip Map.lookup hlm
let eLabel = hooplLabelFor $ Label "entry"
p' <- runConstProp registers hooplLabelFor eLabel prog
return p'
...
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