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c++ - 双击“Laser On” 双击“Laser Off” - Arduino

问题描述

谢谢大家的时间。我有我的代码，当我按住按钮时，激光打开“高”，当我从按钮上松开手指时，激光关闭“低”

但是我想当我双击激光打开时，当我再次双击激光关闭时。

谢谢你，对不起我的英语不好。

const int btn = 6;// The push button
int previousButtonStateLAZER = HIGH;   // for btn6

void setup(){
  pinMode(btn, INPUT);
  pinMode (laserPin, OUTPUT);
}

void loop(){
  int buttonStateLAZER = digitalRead(btn);

  // if the button state has changed,
  if (buttonStateLAZER != previousButtonStateLAZER){
    if( buttonStateLAZER == HIGH ) {
      digitalWrite (laserPin, HIGH);
    }else{
      digitalWrite (laserPin, LOW);
    }
  }
  previousButtonStateLAZER = buttonStateLAZER;
}```

标签： c++carduinoarduino-uno

解决方案

您需要存储检测到点击的最后两次，然后测试它们是否足够靠近。试试这个代码（根据您发布的内容进行编辑）：

const int btn = 6;// The push button
int previousButtonStateLAZER = LOW;   // for btn6

static long releaseTimes[2];
static int releaseIndex = 1;

static int laserStates[2];
static int laserIndex = 0;

void setup(){
  pinMode(btn, INPUT);
  pinMode (laserPin, OUTPUT);

  releaseTimes[0] = 0;
  releaseTimes[1] = 0;

  laserStates[0] = LOW;
  laserStates[1] = HIGH;
}

void loop(){
  int buttonStateLAZER = digitalRead(btn);

  // if the button state has changed,
  if (buttonStateLAZER != previousButtonStateLAZER){
      previousButtonStateLAZER = buttonStateLAZER;

      if (buttonStateLAZER == HIGH) {
          return;
      }

      releaseIndex = 1 - releaseIndex;
      releaseTimes[releaseIndex] = millis();

      if (abs(releaseTimes[0] - releaseTimes[1]) < 800) {
          releaseTimes[0] = 0;
          releaseTimes[1] = 0;
          laserIndex = 1 - laserIndex;
          digitalWrite(laserPin, laserStates[laserIndex]);
      }
  }

}

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