c++ - 程序永远不会超过>>。那是超载的

Question

我正在构建一个名为 的类nim，其中包含大整数。我班级的标题如下所示：

#ifndef NUMAR_INTREG_MARE_H_INCLUDED
#define NUMAR_INTREG_MARE_H_INCLUDED
#include "array.h"
#include <iostream>
class nim///nim=numar_intreg_mare
{
    Array a;//the large integer number
    int semn;//the sign of the number
    int n;//the length of the number
public:
    nim();
    nim(nim const &ob);
    ~nim();
    friend std::ostream& operator<<(std::ostream& os, const nim& ob);
    friend std::istream& operator>>(std::istream& is, nim& ob);
};


#endif // NUMAR_INTREG_MARE_H_INCLUDED

如您所见，它有一个 type 属性Array，这是我构建的另一个类。标题Array是：

#ifndef ARRAY_H_INCLUDED
#define ARRAY_H_INCLUDED
#include <iostream>
class Array{
private:
    int* c;
    int len, capacity;
public:
    Array();
    void Append(int);
    ~Array();
    int& operator[] (int) const;
    void Afisare();//outputiing the array
    friend class nim;
};

#endif // ARRAY_H_INCLUDED

我构建了这个类，以便我可以动态分配内存，正如您从Append工作原理中看到的那样：

#include "array.h"
#include <iostream>
 Array::Array()
    {
        capacity=1;
        c=new int[capacity];
        len=0;
    }
void Array::Append(int x)
    {
        int* temp;
        if(len>=capacity)
        {
            temp=new int[2*capacity];
            for(int i=0; i<capacity; i++)
            {
                temp[i]=c[i];
            }
            capacity*=2;
            delete[] c;
            c=temp;
        }
        c[len]=x;
        len++;
    }
Array::~Array()
    {
            delete[]c;
    }

int& Array::operator[] (int x) const
    {
        return c[x];
    }
void Array::Afisare()
    {
        for(int i=0; i<len; i++)
            std::cout<<c[i]<<" ";
        std::cout<<"\n";
    }

回到我原来的nim课程，这就是我实现这些功能的方式：

#include "numar_intreg_mare.h"
#include <iostream>
nim::nim() : semn(0)
{
    Array a;
}
nim::nim(nim const &ob) : a(ob.a), semn(ob.semn), n(ob.n){}
nim::~nim(){}
std::ostream& operator<< (std::ostream &os, const nim &ob)
{
    if(ob.semn==-1) os<<"-";
    else if(ob.semn==1) os<<"+";
    for(int i=0; i<ob.n; i++)
    {
        os<<ob.a[i];
    }
    os<<"\n";
    return os;
}
std::istream& operator>>(std::istream& is, nim &ob)
{
    std::cout<<"n=";
    int n, semn;
    is>>n;
    ob.n=n;
    std::cout<<"semn=";
    is>>semn;
    ob.semn=semn;
    std::cout<<"a=";
    for(int j = 0; j < ob.n; j++)
        is >> ob.a[j];
    return is;
}

现在，当我main.cpp看起来像这样时：

#include <iostream>
#include "array.h"
#include "numar_intreg_mare.h"
using namespace std;

int main()
{
    nim nr;
    cin>>nr;
    cout<<"gets past cin";
    cout<<nr;
    return 0;
}

我的程序从不输出“gets past cin”所以..它没有过去cin。问题是它不能逐个字符地读取，我必须小心在一个字符后总是按回车键。有谁知道如何让它逐个字符地读取？

标签： c++arraysoperator-overloading